c# - 按钮 onClick 不会与对象发生碰撞

Question

我正在制作一个移动项目，在立方体 RigidBody 的左右和上方有两个碰撞器，它们用鼠标控制。当我按下 Button 立方体 isKinematic = false 但问题是当它与对撞机发生碰撞时我想 Instantiate 一个新的立方体然后运行相同的过程.我写了代码，但它不工作。一个立方体下落，第二个立方体被实例化，它不执行onClick。

立方体脚本:

   public class CubeScript : MonoBehaviour
{

    private float pos;
    private bool fall;
    private bool exit;
    [SerializeField]
    private Rigidbody2D body;

    void Awake ()
    {

        body.isKinematic = true;

        fall = true;

        exit = true;



    }

    void Update ()
    {

        if (fall) {

            Vector3 temp = transform.position;

            pos = Camera.main.ScreenToWorldPoint (Input.mousePosition).x;

            temp.x = Mathf.Clamp (pos, -2.73f, 2.73f);

            body.position = temp;

            if (exit) {

                return;  
            }
        }
    }



}

左对撞机:

    public class LeftCollider : MonoBehaviour
{

    public GameObject cube;

    [SerializeField]
    private BoxCollider2D collide;

   [SerializeField]
   private GameObject CubeClone;

   private Button touchbutton;

    void Awake ()
    {
        collide.isTrigger = true;


        touchbutton = GameObject.FindGameObjectWithTag ("TouchButton").GetComponent<Button> ();

        touchbutton.onClick.AddListener (() => CubeShoot ());



    }

    void OnTriggerEnter2D (Collider2D col)
    {
        Destroy (col.gameObject);
        cube = Instantiate (CubeClone, new Vector3 (0f, 1.934f, 0f), Quaternion.identity) as GameObject;
    }

    public void CubeShoot ()
    {
        cube.GetComponent<Rigidbody2D> ().isKinematic = false;
    }

}

右对撞机:

  public class RightCollider : MonoBehaviour
{

    public GameObject cube;

    [SerializeField]
    private BoxCollider2D collide;

   [SerializeField]
    private GameObject CubeClone;

    private Button touchbutton;

    void Awake ()
    {
        collide.isTrigger = true;

        touchbutton = GameObject.FindGameObjectWithTag ("TouchButton").GetComponent<Button> ();

        touchbutton.onClick.AddListener (() => CubeShoot ());


    }

    void OnTriggerEnter2D (Collider2D col)
    {
        Destroy (col.gameObject);
        cube = Instantiate (CubeClone, new Vector3 (0f, 1.934f, 0f), Quaternion.identity);
    }

    public void CubeShoot ()
    {
        cube.GetComponent<Rigidbody2D> ().isKinematic = false;
    }

}

图像

Answer 1

这个问题有点相似，但现在你有 2 个对撞机:

Button click does not work correctly

根据实际编程，我让它工作的方式是:

对于 Collider(对于两者 - 注意第一行，我粘贴的是 LeftCollider，另一个应该是 RightCollider):

public class LeftCollider : MonoBehaviour {

    //public GameObject cube;

    [SerializeField]
    private BoxCollider2D collide;


    [SerializeField]
    private GameObject CubeClone;

    private Button touchbutton;


    void Awake(){
        collide.isTrigger = true;


        touchbutton = GameObject.FindGameObjectWithTag ("TouchButton").GetComponent<Button> ();

        touchbutton.onClick.AddListener (() => CubeShoot ());



    }

    void OnTriggerEnter2D(Collider2D col){
        Destroy (col.gameObject);
        Instantiate (CubeClone, new Vector3 (0f, 1.934f, 0f), Quaternion.identity);
    }




    public void CubeShoot ()
    {
        GameObject.FindGameObjectWithTag("cube").GetComponent<Rigidbody2D> ().isKinematic = false;
    }


}

在预制件上放置标签:“立方体”(还要检查标签是否在事件立方体上，即一个层次结构)

应该这样做。