ios - 有没有办法像这样向 NSOperationQueue 添加 block

Question

我正在尝试理解 NSOperationQueue，并尝试创建尽可能简单的示例。我有以下内容:

NSOperationQueue *myOQ=[[NSOperationQueue alloc] init];

[myOQ addOperationWithBlock:^(void){
  NSLog(@"here is something for jt 2");
}];
[myOQ addOperationWithBlock:^(void){
  NSLog(@"oh is this going to work 2");
}];

但是想这样做:

void  (^jt)() = ^void(){
  NSLog(@"here is something for jt");
};

void (^cl)() = ^void(){
  NSLog(@"oh is this going to work");
};

NSOperationQueue *myOQ=[[NSOperationQueue alloc] init];

[myOQ addOperation:jt];
[myOQ addOperation:cl];

后一种形式可能吗？我可以将 block 转换为 NSOperation 吗？

提前谢谢

Answer 1

你可以:

NSBlockOperation *jtOperation = [NSBlockOperation blockOperationWithBlock:^{
    NSLog(@"here is something for jt");
}];

NSBlockOperation *clOperation = [NSBlockOperation blockOperationWithBlock:^{
    NSLog(@"oh is this going to work");
}];

[myOQ addOperation:jtOperation];
[myOQ addOperation:clOperation];

话虽如此，我通常会执行 addOperationWithBlock 除非出于某些其他原因(例如建立操作之间的依赖关系等)我真的需要 NSOperation 对象指针.