我正在使用 Web 表单,我的 ajax 函数调用的代码背后有一个 Web 方法。看起来 web 方法正在返回数据,但我无法将返回的 json 字符串解析为表行
这是我的代码隐藏方法(Web 方法):
public class Part
{
public string Number { get; set; }
public string Price { get; set; }
public string NetAvailable { get; set; }
public string Location { get; set; }
public string Distance { get; set; }
public string Phone { get; set; }
}
[WebMethod]
public static List<Part> GetParts(string partnumber)
{
List<Part> parts = new List<Part>();
using (SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["NXT"].ToString()))
{
con.Open();
using (SqlCommand command = new SqlCommand("SELECT prod, qtyonhand, whse, listprice FROM icsw where prod LIKE @partnumber", con))
{
command.Parameters.AddWithValue("@partnumber", "%" + partnumber + "%");
using (SqlDataReader reader = command.ExecuteReader())
{
while (reader.Read())
{
Part part = new Part
{
Number = reader[0].ToString(),
Price = reader[3].ToString(),
NetAvailable = reader[1].ToString(),
Distance = "0.0",
Location = reader[2].ToString(),
Phone = GetBranchPhoneNumber(reader[2].ToString())
};
parts.Add(part);
}
}
}
}
return parts;
}
这是我的 AJAX 调用:
$("#searchbtn").click(function() {
$.ajax({
url: 'partslocator.aspx/GetParts',
type: 'POST',
data: JSON.stringify({ 'partnumber': $("#searchtbx").val()}),
dataType: 'json',
contentType: 'application/json',
success: function (data) {
for (var i in data) {
alert(JSON.stringify(data[i]));
$('#searchresultstble').append("<tr><td>" + data[i].Number + "</td><td>" + data[i].Price + "</td><td>" + data[i].NetAvailable + "</td><td>" + data[i].Location + "</td><td>" + data[i].Distance + "</td><td>" + data[i].Phone + "</td></tr>");
}
},
error: function (xhr, ajaxOptions, thrownError) {
alert(xhr.status);
alert(thrownError);
}
});
});
这是返回的数据:
{"d":[{"__type":"partslocator+Part","Number":"0-2809 1025","Price":"2.50000","NetAvailable":"0.00","Location":"82pk","Distance":"0.0","Phone":"test"},{"__type":"partslocator+Part","Number":"0-2809 1025","Price":"2.58000","NetAvailable":"0.00","Location":"Phx","Distance":"0.0","Phone":"test"}]}
为什么添加的所有行都未定义?
最佳答案
您会注意到返回的 data
实际上不是一个数组,而是一个包含该数组的值 (d
) 的对象。试试这个:
success: function (returnedData) {
var data = returnedData.d;
for (var i in data) {
alert(JSON.stringify(data[i]));
$('#searchresultstble').append("<tr><td>" + data[i].Number + "</td><td>" + data[i].Price + "</td><td>" + data[i].NetAvailable + "</td><td>" + data[i].Location + "</td><td>" + data[i].Distance + "</td><td>" + data[i].Phone + "</td></tr>");
}
},
关于c# - 在 AJAX 成功函数中解析返回的 C# 列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33508689/