c# - 使用 MVC Controller 重载

Question

我有一个同名的操作，一个不需要参数，另一个需要一个 ID，当我尝试浏览我的 url 时，我得到以下异常。

An unhandled exception occurred while processing the request.

AmbiguousActionException: Multiple actions matched. The following actions matched route data and had all constraints satisfied:

Mailer.Controllers.MailBuilderController.MailBody (Mailer) Mailer.Controllers.MailBuilderController.MailBody (Mailer)

我的 MailBuilder Controller 。

//[HttpGet("mailbuilder/MailBody")]
public IActionResult MailBody()
{
   Body model = new Body();
   return View(model);
}

//[HttpGet("mailbuilder/MailBody/{id}")]
public IActionResult MailBody(int id)
{
   Body model = _mailBuilderService.GetBody(id);
   return View(model);
}

如果我删除上面的评论，我可以导航，但我无法重定向到以下方法中的操作。

public IActionResult SaveBody(Body model)
{
  _mailBuilderService.AddBody(model);
  return RedirectToAction("MailBody", model.Id);
}

Answer 1

如果它与以前版本的 MVC 有任何相似之处，那么您将需要取消注释那些路由属性 ([HttpGet("mailbuilder/MailBody/{id}")])，同时重命名您的帖子同名 Action 。或者，您可以在表单助手中设置操作(如果它仍然存在)。

此外，路由器还可以找到您需要将路由数据作为对象提供的正确方法 return RedirectToAction("MailBody", new { id = model.Id });

以下代码示例未经测试，但我认为它会走在正确的轨道上......

[HttpGet("mailbuilder/MailBody")]
public IActionResult MailBody()
{
   Body model = new Body();
   return View(model);
}

[HttpGet("mailbuilder/MailBody/{id}")]
public IActionResult MailBody(int id)
{
   Body model = _mailBuilderService.GetBody(id);
   return View(model);
}

[HttpPost("mailbuilder/MailBody")]
public IActionResult MailBody(Body model)
{
  _mailBuilderService.AddBody(model);
  return RedirectToAction("MailBody", new { id = model.Id });
}