c# - 我该如何解决 "The query results cannot be enumerated more than once"？

Question

如果我尝试编写以下代码:错误返回给我:查询结果不能枚举多次

  public void StartTransaction()
        {
            using (var stockMovementCtx = new StockMovementCtxDataContext())
            using (var scope = new TransactionScope())
            {

                var stockMovementItems = from s in stockMovementCtx.spStockMovementForTransaction(TicketID, ItemTypeNo, ItemID, TransactionType,
                                                                                                  FromLocation, ToLocation, Qty, PersonelNo, cuser
                                                                                                  )
                                         select s;

                ReturnCode = stockMovementItems.First().ReturnCode;
               // MessageBox.Show(stockMovementItems.First().ToString());
                ReturnMsg = stockMovementItems.First().ReturnMessage;
                TransactionType = stockMovementItems.First().TransactionType;
                TicketID = stockMovementItems.First().TicketID;

详细信息:

详细信息:

Answer 1

我不熟悉这个错误。
但无论如何 - 你为什么要枚举不止一次？
只用一个枚举会更有效率。

public void StartTransaction()
        {
            using (var stockMovementCtx = new StockMovementCtxDataContext())
            using (var scope = new TransactionScope())
            {

                var stockMovementItems = from s in stockMovementCtx.spStockMovementForTransaction(TicketID, ItemTypeNo, ItemID, TransactionType,
                                                                                                  FromLocation, ToLocation, Qty, PersonelNo, cuser
                                                                                                  )
                                         select s;

                var item = stockMovementItems.FirstOrDefault()
                if (item != null)
                {
                    ReturnCode = (item.ReturnCode;
                   // MessageBox.Show((item.ToString());
                    ReturnMsg = item.ReturnMessage;
                    TransactionType = item.TransactionType;
                    TicketID = item.TicketID;