我有一个非常大的位图,我正尝试使用 C# 应用程序查看它。
这里的主要问题是我无法将它直接加载到内存中,因此我尝试使用内存映射 View 库使用来自 Reference One 的指南加载它。 , Reference Two , Reference Three , Reference Four和 Reference Five .
到目前为止我达到的是以下内容:- 根据需要分部分读取位图(例如,我读取了前 200 行)。 从我读取的行创建另一个位图并显示它。
问题:- 重建后的位图图像部分丢失了颜色信息,上下颠倒显示。
示例:- [注意我在这里使用小尺寸图像并尝试显示它的一部分以进行测试]
真实形象:-
输出应该是(选择前 200 行并重建一个较小的位图并显示它):- 正如您所看到的,重建的图像是无色的并且是上下颠倒的。
现在是代码部分:- 负责整个过程的BMPMMF类
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.IO.MemoryMappedFiles;
using System.Drawing;
using System.Runtime.InteropServices;
using System.Drawing.Imaging;
namespace BMPViewer
{
class BMPMMF
{
/// <summary>
/// It opens the image using memory mapped view and read the needed
/// parts, then call CreateBM to create a partially bitmap
/// </summary>
/// <param name="bmpFilename">Path to the physical bitmap</param>
/// <returns></returns>
public Bitmap readPartOfImage(string bmpFilename)
{
var headers = ReadHeaders(bmpFilename);
var mmf = MemoryMappedFile.CreateFromFile(bmpFilename, FileMode.Open);
int rowSize = headers.Item2.RowSize; // number of byes in a row
// Dictionary<ColorObject, int> rowColors = new Dictionary<ColorObject, int>();
int colorSize = Marshal.SizeOf(typeof(MyColor));
int width = rowSize / colorSize;//(headers.Item1.DataOffset+ rowSize) / colorSize;
int height = 200;
ColorObject cObj;
MyColor outObj;
ColorObject[][] rowColors = new ColorObject[height][];
// Read the view image and save row by row pixel
for (int j = 0; j < height; j++)
{
rowColors[j] = new ColorObject[width];
using (var view = mmf.CreateViewAccessor(headers.Item1.DataOffset + rowSize * j, rowSize, MemoryMappedFileAccess.Read))
{
for (long i = 0; i < rowSize; i += colorSize)
{
view.Read(i, out outObj);
cObj = new ColorObject(outObj);
rowColors[j][i / colorSize] = cObj;
}
}
}
return CreateBM( rowColors );
}
/// <summary>
/// Used to create a bitmap from provieded bytes
/// </summary>
/// <param name="rowColors">Contains bytes of bitmap</param>
/// <returns></returns>
private Bitmap CreateBM(ColorObject[][] rowColors )
{
int width = rowColors[0].Count();
int height = rowColors.Count();
//int width = rowColors.Values.Where(o => o == 0).Count();
Bitmap bitm = new Bitmap(width, height, PixelFormat.Format24bppRgb);
// new Bitmap(imgdat.GetUpperBound(1) + 1, imgdat.GetUpperBound(0) + 1, PixelFormat.Format24bppRgb);
BitmapData bitmapdat = bitm.LockBits(new Rectangle(0, 0, bitm.Width, bitm.Height), ImageLockMode.ReadWrite, bitm.PixelFormat);
int stride = bitmapdat.Stride;
byte[] bytes = new byte[stride * bitm.Height];
for (int r = 0; r < bitm.Height; r++)
{
for (int c = 0; c < bitm.Width; c++)
{
ColorObject color = rowColors[r][c];
bytes[(r * stride) + c * 3] = color.Blue;
bytes[(r * stride) + c * 3 + 1] = color.Green;
bytes[(r * stride) + c * 3 + 2] = color.Red;
}
}
System.IntPtr scan0 = bitmapdat.Scan0;
Marshal.Copy(bytes, 0, scan0, stride * bitm.Height);
bitm.UnlockBits(bitmapdat);
return bitm;
}
/// <summary>
/// Returns a tuple that contains necessary information about bitmap header
/// </summary>
/// <param name="filename"></param>
/// <returns></returns>
private Tuple<BmpHeader, DibHeader> ReadHeaders(string filename)
{
var bmpHeader = new BmpHeader();
var dibHeader = new DibHeader();
using (var fs = new FileStream(filename, FileMode.Open, FileAccess.Read))
{
using (var br = new BinaryReader(fs))
{
bmpHeader.MagicNumber = br.ReadInt16();
bmpHeader.Filesize = br.ReadInt32();
bmpHeader.Reserved1 = br.ReadInt16();
bmpHeader.Reserved2 = br.ReadInt16();
bmpHeader.DataOffset = br.ReadInt32();
dibHeader.HeaderSize = br.ReadInt32();
if (dibHeader.HeaderSize != 40)
{
throw new ApplicationException("Only Windows V3 format supported.");
}
dibHeader.Width = br.ReadInt32();
dibHeader.Height = br.ReadInt32();
dibHeader.ColorPlanes = br.ReadInt16();
dibHeader.Bpp = br.ReadInt16();
dibHeader.CompressionMethod = br.ReadInt32();
dibHeader.ImageDataSize = br.ReadInt32();
dibHeader.HorizontalResolution = br.ReadInt32();
dibHeader.VerticalResolution = br.ReadInt32();
dibHeader.NumberOfColors = br.ReadInt32();
dibHeader.NumberImportantColors = br.ReadInt32();
}
}
return Tuple.Create(bmpHeader, dibHeader);
}
}
public struct MyColor
{
public byte Red;
public byte Green;
public byte Blue;
//public byte Alpha;
}
public class ColorObject
{
public ColorObject(MyColor c)
{
this.Red = c.Red;
this.Green = c.Green;
this.Blue = c.Blue;
// this.Alpha = c.Alpha;
}
public byte Red;
public byte Green;
public byte Blue;
// public byte Alpha;
}
public class BmpHeader
{
public short MagicNumber { get; set; }
public int Filesize { get; set; }
public short Reserved1 { get; set; }
public short Reserved2 { get; set; }
public int DataOffset { get; set; }
}
public class DibHeader
{
public int HeaderSize { get; set; }
public int Width { get; set; }
public int Height { get; set; }
public short ColorPlanes { get; set; }
public short Bpp { get; set; }
public int CompressionMethod { get; set; }
public int ImageDataSize { get; set; }
public int HorizontalResolution { get; set; }
public int VerticalResolution { get; set; }
public int NumberOfColors { get; set; }
public int NumberImportantColors { get; set; }
public int RowSize
{
get
{
return 4 * ((Bpp * Width) / 32);
}
}
}
}
这是如何使用它:-
Bitmap bmpImage = bmp.readPartOfImage(filePath); // path to bitmap
pictBoxBMP.Image = bmpImage; // set the picture box image to the new Partially created bitmap
我寻求的解决方案:- 正确显示部分创建的位图,我猜测位图重建或使用内存映射 View 读取位图有问题。
更新#1:申请后 @TaW solution我得到了显示的颜色,即使它们与原始颜色有点不同,但它被接受了。
最佳答案
对于反转部分,您必须检查输入位图数据的顺序(自下而上或自上而下)。 您可以通过检查 DibHeader Height 属性的符号来执行此操作。 通常,负高度表示自上而下的布局。 https://msdn.microsoft.com/en-us/library/windows/desktop/dd183376%28v=vs.85%29.aspx
然后您知道是否必须反转数据,将输入位图的第一行复制到目标位图的最后一行。
for (int r = 0; r < bitm.Height; r++)
{
for (int c = 0; c < bitm.Width; c++)
{
ColorObject color = rowColors[r][c];
bytes[( (bitm.Height - r - 1) * stride) + c * 3] = color.Blue;
bytes[( (bitm.Height - r - 1) * stride) + c * 3 + 1] = color.Green;
bytes[( (bitm.Height - r - 1) * stride) + c * 3 + 2] = color.Red;
}
}
关于c# - 使用内存映射 View 查看大位图图像,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28310592/