c# - 如何正确使用 HttpClient PostAsync 参数？

Question

所以我正在使用 HttpClient 为我的项目编写一个扩展类，因为我要从 HttpWebRequest 转移过来。

POST请求时，如何发送一个普通的字符串作为参数？没有 json 或任何东西只是一个简单的字符串。

这是到目前为止的样子。

static class HttpClientExtension
    {
        static HttpClient client = new HttpClient();
        public static string GetHttpResponse(string URL)
        {
            string fail = "Fail";
            client.BaseAddress = new Uri(URL);
            HttpResponseMessage Response = client.GetAsync(URL).GetAwaiter().GetResult();
            if (Response.IsSuccessStatusCode)
                return Response.Content.ReadAsStringAsync().GetAwaiter().GetResult();
            else
                return fail;
        }

        public static string PostRequest(string URI, string PostParams)
        {
            client.PostAsync(URI, new StringContent(PostParams));
            HttpResponseMessage response = client.GetAsync(URI).GetAwaiter().GetResult();
            string content = response.Content.ReadAsStringAsync().GetAwaiter().GetResult();
            return content;
        }
    }

如果你这样看

client.PostAsync(URI, new StringContent(PostParams));

您可以看到，我刚刚尝试创建新的 StringContent 并将一个字符串传递给它，响应返回 404 页面未找到。 我如何正确使用 Post.Async();发送字符串或字节数组？因为使用 HttpWebRequest 你会这样做

public static void SetPost(this HttpWebRequest request, string postdata)
        {
            request.Method = "POST";
            byte[] bytes = Encoding.UTF8.GetBytes(postdata);

            using (Stream requestStream = request.GetRequestStream())
                requestStream.Write(bytes, 0, bytes.Length);
        }

Answer 1

在 PostRequest 中完成以下操作..

client.PostAsync(URI, new StringContent(PostParams));
HttpResponseMessage response = client.GetAsync(URI).GetAwaiter().GetResult();

它不捕获 POST 的响应。

重构为

public static string PostRequest(string URI, string PostParams) {            
    var response = client.PostAsync(URI, new StringContent(PostParams)).GetAwaiter().GetResult();
    var content = response.Content.ReadAsStringAsync().GetAwaiter().GetResult();
    return content;
}

HttpClient 主要用于异步使用，因此请考虑重构为

public static async Task<string> PostRequestAsync(string URI, string PostParams) {            
    var response = await client.PostAsync(URI, new StringContent(PostParams));
    var content = await response.Content.ReadAsStringAsync();
    return content;
}