c# - 将字符串转换为 double : input string was not in a correct format

Question

我正在通过串行端口从我的 Arduino 获取一些值。数据具有以下格式: "value1,value2,value3\r" 作为 string。

示例:"4.5,550.0,0.02\r"

我可以接收并分隔这些值，但是当我尝试将它们转换为 double 时，出现以下异常

"input string was not in a correct format"`.

double Battery = 0, Voltage = 0, Current = 0;

private void serialPort1_DataReceived(object sender, SerialDataReceivedEventArgs e)
{
    string data = serialPort1.ReadLine();
    string bv = data.Substring(0, data.IndexOf(",") - 1);
    data = data.Substring(data.IndexOf(",") + 1);
    string v0 = data.Substring(0, data.IndexOf(",") - 1);
    data = data.Substring(data.IndexOf(",") + 1);
    string i = data;

    double batteryVoltage = Convert.ToDouble(bv);
    double V0 = Convert.ToDouble(v0);
    double I = Convert.ToDouble(i);

    Battery = batteryVoltage;
    Voltage = V0;
    Current = I;

}

Answer 1

这里有两个问题。首先，由于区域设置(无效的小数点字符)，转换可能会失败，因此使用 System.Globalization 命名空间中的 CultureInfo.InvariantCulture 作为附加参数。第二，您要从子字符串中删除一个字符，因此删除 -1。

string data = "4.5,550.0,0.02\r";
string bv = data.Substring(0, data.IndexOf(","));
data = data.Substring(data.IndexOf(",") + 1);
string v0 = data.Substring(0, data.IndexOf(","));
data = data.Substring(data.IndexOf(",") + 1);
string i = data;

double batteryVoltage = Convert.ToDouble(bv, CultureInfo.InvariantCulture);
double V0 = Convert.ToDouble(v0, CultureInfo.InvariantCulture);
double I = Convert.ToDouble(i, CultureInfo.InvariantCulture);