c# - 弹出菜单 windows phone 8.1 暂停 Listview

Question

当在 listview 上使用 hold 项目时，如何显示 flyout 菜单？我试过了，但是 hold 方法引用了 listview 而不是它自己的项目。

Answer 1

您可以订阅项目的模板持有事件。例如像这样:

<ListView.ItemTemplate>
    <DataTemplate>
        <Grid Holding="Grid_Holding" VerticalAlignment="Stretch">
            <FlyoutBase.AttachedFlyout>
                <MenuFlyout>
                    <MenuFlyoutItem x:Name="EditButton"
                            Text="Edit"
                            Click="EditButton_Click"/>
                    <MenuFlyoutItem x:Name="DeleteButton"
                            Text="Delete"
                            Click="DeleteButton_Click"/>
                </MenuFlyout>
            </FlyoutBase.AttachedFlyout>
            <TextBlock Text="{Binding}" VerticalAlignment="Center"/>
        </Grid>
    </DataTemplate>
</ListView.ItemTemplate>

在后面的代码中，显示弹出窗口:

private void Grid_Holding(object sender, HoldingRoutedEventArgs e)
{
    FrameworkElement senderElement = sender as FrameworkElement;
    // If you need the clicked element:
    // Item whichOne = senderElement.DataContext as Item;
    FlyoutBase flyoutBase = FlyoutBase.GetAttachedFlyout(senderElement);
    flyoutBase.ShowAt(senderElement);
}

private async void EditButton_Click(object sender, RoutedEventArgs e)
{
    // get the clicked element:
    Item datacontext = (e.OriginalSource as FrameworkElement).DataContext as Item;
    await new MessageDialog("Edit").ShowAsync();
}

如果您愿意，您也可以使用 Behaviours 来完成。您还可以在 Igrali's blog post 找到一些帮助.