我有一个一维整数数组:
int[] array = { 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32,33, 34,40,41,42,43, 44};
我想将这个一维数组分成 4 行 5 列的二维数组,其中前 5 个值进入第 1 行,接下来的 5 个值进入第 2 行,依此类推。最终结果应该是这样的:
二维数组:
[[10, 11, 12, 13, 14]
[20, 21, 22, 23, 24]
[30, 31, 32, 33, 34]
[40, 41, 42, 43, 44]]
实际上数组会更长(可能超过 100 行),但是列数是 5,行数可以被 5 整除。例如我已经简化了。到目前为止,这是我尝试过的:
int[] array = { 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32,33, 34,40,41,42,43, 44};
int[,] array2D = new int[(array.Length/5),5];
int count_0 = 1;
int count_1 = 1;
int count_2 = 1;
int count_3 = 1;
int count_4 = 1;
for (int i = 0; i < array.Length; i++)
{
if (i < 5)
{
// works for the first 5 values:
array2D[0, i] = array[i];
}
// I tried this approach for the rest where I try to say that if Im at index 5,
//and every 5th element from here, append to it to index[i,0] of array2D and so on.
// This do not work, and is what I need help with.
else if (i >= 5 && i % 5 == 0)
{
array2D[count_0, 0] = array[i];
count_0++;
}
else if (i >= 6 && i % 5 == 0)
{
array2D[count_1, 1] = array[i];
count_1++;
}
else if (i >= 7 && i % 5 == 0)
{
array2D[count_2, 2] = array[i];
count_2++;
}
else if (i >= 8 && i % 5 == 0)
{
array2D[count_3, 3] = array[i];
count_3++;
}
else if (i >= 9 && i % 5 == 0)
{
array2D[count_4, 4] = array[i];
count_4++;
}
}
当然对于这个例子我可以说if > 5 && <10 {append to array2D}
和 if > 10 && <15 {append to array2D}
等等,但我想要一些适用于大量数百个值的东西。如果有人有更聪明的方法来做到这一点,请告诉我。
感谢您的帮助!
最佳答案
你可以只计算索引:
for(int i=0;i<array.Length;i++)
array2D[i/5, i%5] = array[i];
关于C# 将 1D 数组拆分为每个第 N 个值的 2D 数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52444323/