c# - DataGridView 不在 ToolStripDropDown 中显示数据

Question

我在这里使用 Jesper Palm 发布的代码:Make user control display outside of form boundry

/// <summary>
/// A simple popup window that can host any System.Windows.Forms.Control
/// </summary>
public class PopupWindow : System.Windows.Forms.ToolStripDropDown
{
    private System.Windows.Forms.Control _content;
    private System.Windows.Forms.ToolStripControlHost _host;

    public PopupWindow(System.Windows.Forms.Control content)
    {
        //Basic setup...
        this.AutoSize = false;
        this.DoubleBuffered = true;
        this.ResizeRedraw = true;

        this._content = content;
        this._host = new System.Windows.Forms.ToolStripControlHost(content);

        //Positioning and Sizing
        this.MinimumSize = content.MinimumSize;
        this.MaximumSize = content.Size;
        this.Size = content.Size;
        content.Location = Point.Empty;

        //Add the host to the list
        this.Items.Add(this._host);
    }
}

我已经将它翻译成 VB:

Public Class PopupWindow
    Inherits System.Windows.Forms.ToolStripDropDown

    Private _content As System.Windows.Forms.Control
    Private _host As System.Windows.Forms.ToolStripControlHost

    Public Sub New(ByVal content As System.Windows.Forms.Control)

        Me.AutoSize = False
        Me.DoubleBuffered = True
        Me.ResizeRedraw = True

        Me._content = content
        Me._host = New System.Windows.Forms.ToolStripControlHost(content)

        Me.MinimumSize = content.MinimumSize
        Me.MaximumSize = content.MaximumSize
        Me.Size = content.Size
        content.Location = Point.Empty

        Me.Items.Add(Me._host)

    End Sub

End Class

它与显示其信息的 PictureBox 配合使用效果很好。但是由于某种原因，我无法让 DataGridView 在弹出窗口中显示任何内容。

如果我将网格从弹出窗口中拉出，它会很好地显示所有信息。如果我在调试期间暂停，网格会显示其中包含所有数据。它只是不显示任何内容。

有没有人有什么想法？

Answer 1

我无法重现您的问题。你能提供更多的代码吗？我一直在 VS2010 RC (.NET 4) 和 VS2008 (.NET 3.5) 中进行测试，这段代码在两者中都有效:

public partial class Form1 : Form
{
    public class Person
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public string PhoneNumber { get; set; }
    }

    List<Person> _People;

    public Form1()
    {
        InitializeComponent();

        _People = new List<Person>();
        _People.Add(new Person() { FirstName = "John", LastName = "Smith", PhoneNumber = "123-456-7890" });
        _People.Add(new Person() { FirstName = "Jane", LastName = "Doe", PhoneNumber = "098-765-4321" });
    }

    private void Form1_Load(object sender, EventArgs e)
    {
        pictureBox1.Image = Image.FromFile("barcode.png");
        pictureBox1.Location = new Point(-1000, -1000);

        dataGridView1.DataSource = _People;
        dataGridView1.Location = new Point(-1000, -1000);
    }

    private void button1_Click(object sender, EventArgs e)
    {
        PopupControl popup = new PopupControl(pictureBox1);
        popup.Show(new Point(this.Location.X - 128, this.Location.Y));
    }

    private void button2_Click(object sender, EventArgs e)
    {
        PopupControl popup = new PopupControl(dataGridView1);
        popup.Show(new Point(this.Location.X - 128, this.Location.Y));

        //optionally change the items in the data source
        _People.Add(new Person() { FirstName = "NewFirst", LastName = "NewLast", PhoneNumber = "123-333-3322" });

        //reset the bindings
        bindingSource1.DataSource = _People;
        bindingSource1.ResetBindings(true);
    }
}

这是它的样子: alt text http://img534.imageshack.us/img534/1640/popupcontrolwithgrid.jpg

在设计器中，您应该设置 BindingSource 并将其指定为 DataGridView 的数据源。