c# - AlreadyAllocated 调用 waveOutOpen 错误

Question

 private void receiveAudio(object sender)
        {
            IPEndPoint senderEP = new IPEndPoint(IPAddress.Any, 0);
            MemoryStream audioDataStream;
            BufferedWaveProvider bufferedWaveProvider; 
            //RawSourceWaveStream receivedRawAudioData;          
            byte[] receivedAudioData;
            waveOutStream = new WaveOut();

            while (IsAudioTransferActive)
            {
                receivedAudioData = audioUDPClient.Receive(ref senderEP);               
                audioDataStream = new MemoryStream(receivedAudioData);                
                //receivedRawAudioData = new RawSourceWaveStream(audioDataStream, audioFormat);
                bufferedWaveProvider = new BufferedWaveProvider(audioFormat);
//How can I feed "audioDataStream " to "bufferedWaveProvider "
                waveOutStream.Init(bufferedWaveProvider);
                waveOutStream.Play();
            } 
            waveOutStream.Stop();
            waveOutStream.Dispose();
        }

@Mark Heath:- 正如你所说，我已经尝试使用 BufferedWaveProvider，但我如何才能为 bufferedWaveProvider 提供“audioDataStream”

Answer 1

您不断在 while 循环中创建未释放的 WaveOut 对象，这是问题的一部分。在这种情况下，最好的方法是创建一个 WaveOut 对象并使用 BufferedWaveProvider 提供给它。然后，当音频可用时，将其写入 BufferedWaveProvider。