ios - 使用 UITapGestureRecognizer 传递参数

Question

有什么方法可以用 UITapGestureRecognizer 传递参数吗？ 我已经看到这个针对 objective-c 的回答，但找不到 swift 的答案

test.userInteractionEnabled = true
let tapRecognizer = UITapGestureRecognizer(target: self, action: Selector("imageTapped4:"))
// Something like text.myParamater
test.addGestureRecognizer(tapRecognizer)

然后在 func imageTapped4() 下接收 myParameter{}

Answer 1

一种方法是继承 UITapGestureRecognizer 然后设置一个属性，我在下面发布了一个示例。您还可以对发件人进行一些检查，并检查是否等于某些标签、类、字符串等

class ViewController: UIViewController {

    @IBOutlet weak var label1: UILabel!
    @IBOutlet weak var image: UIImageView!

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
        image.userInteractionEnabled = true;
        let tappy = MyTapGesture(target: self, action: #selector(self.tapped(_:)))
        image.addGestureRecognizer(tappy)
        tappy.title = "val"
    }

    func tapped(sender : MyTapGesture) {
        print(sender.title)
        label1.text = sender.title
    }
}

class MyTapGesture: UITapGestureRecognizer {
    var title = String()
}

SO上有很多例子，看看吧，祝你好运。