java.lang.AssertionError : one method tests correctly but a similar one does not 错误

Question

我从 DAO 测试了以下 2 种方法:

public List<T> findAll() {
    if (logger.isDebugEnabled()) {
        logger.debug("findAll");
    }
    return currentSession().createCriteria(getPersistentClass()).list();
}

public int count() {
    if (logger.isDebugEnabled()) {
        logger.debug("count");
    }
    return ((Number) currentSession().createCriteria(getPersistentClass()).
            setProjection(Projections.rowCount()).
            uniqueResult()).intValue();
}

测试片段:

@Test
@Transactional(isolation = Isolation.SERIALIZABLE)
public void testFindAll(){
    Assert.assertEquals(2566, this.employeeHibernateDAO.findAll().size());
}

@Test
@Transactional(isolation = Isolation.SERIALIZABLE)
public void testCount(){
    Assert.assertEquals(2566, this.employeeHibernateDAO.count());
}

表中共有 2566 个条目，count 成功返回其计数，但 findAll 没有。

错误:

java.lang.AssertionError: 
Expected :2566
Actual   :0
    at org.junit.Assert.fail(Assert.java:91)
    at org.junit.Assert.failNotEquals(Assert.java:645)
    at org.junit.Assert.assertEquals(Assert.java:126)
    at org.junit.Assert.assertEquals(Assert.java:470)
    at org.junit.Assert.assertEquals(Assert.java:454)
    at com.develop.test.data.dao.EmployeeDAOTest.testFindAll(EmployeeDAOTest.java:53)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
    at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
    at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
    at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
    at org.springframework.test.context.junit4.statements.RunBeforeTestMethodCallbacks.evaluate(RunBeforeTestMethodCallbacks.java:74)
    at org.springframework.test.context.junit4.statements.RunAfterTestMethodCallbacks.evaluate(RunAfterTestMethodCallbacks.java:82)
    at org.springframework.test.context.junit4.statements.SpringRepeat.evaluate(SpringRepeat.java:72)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:240)
    at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:49)
    at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193)
    at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52)
    at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191)
    at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42)
    at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184)
    at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61)
    at org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:70)
    at org.junit.runners.ParentRunner.run(ParentRunner.java:236)
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:180)
    at org.junit.runner.JUnitCore.run(JUnitCore.java:157)
    at com.intellij.junit4.JUnit4IdeaTestRunner.startRunnerWithArgs(JUnit4IdeaTestRunner.java:71)
    at com.intellij.rt.execution.junit.JUnitStarter.prepareStreamsAndStart(JUnitStarter.java:199)
    at com.intellij.rt.execution.junit.JUnitStarter.main(JUnitStarter.java:62)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120)

鉴于该错误，它实际上在该特定方法上返回 0。我不明白为什么考虑计数是成功的。有帮助吗？

编辑: count() 的 SQL:

09:56:15.180 [main] DEBUG org.hibernate.SQL - 
    select
        count(*) as y0_ 
    from
        EMPLOYEE this_
Hibernate: 
    select
        count(*) as y0_ 
    from
        EMPLOYEE this_

findAll() 的 SQL(employee3 指的是 Updated-By 字段):

09:56:15.243 [main] DEBUG org.hibernate.SQL - 
    select
        this_.EMP_ID as EMP1_5_2_,
        this_.ISACTIVE as ISACTIVE5_2_,
        this_.COMPANY_CODE as COMPANY12_5_2_,
        this_.CORP_TITLE as CORP3_5_2_,
        this_.DEPT_CODE as DEPT13_5_2_,
        this_.E_MAIL as E4_5_2_,
        this_.EMP_FIRST_NAME as EMP5_5_2_,
        this_.HIRE_DATE as HIRE6_5_2_,
        this_.JOB_CODE as JOB7_5_2_,
        this_.JOB_TITLE_DESC as JOB8_5_2_,
        this_.EMP_LAST_NAME as EMP9_5_2_,
        this_.MANAGER_ID as MANAGER14_5_2_,
        this_.MANAGER_INDC as MANAGER10_5_2_,
        this_.EMP_MIDDLE_NAME as EMP11_5_2_,
        preference2_.EMP_ID as EMP1_13_0_,
        preference2_.UPDATED_BY as UPDATED4_13_0_,
        preference2_.UPDATED_DATE as UPDATED2_13_0_,
        preference2_.LANGUAGE as LANGUAGE13_0_,
        employee3_.EMP_ID as EMP1_5_1_,
        employee3_.ISACTIVE as ISACTIVE5_1_,
        employee3_.COMPANY_CODE as COMPANY12_5_1_,
        employee3_.CORP_TITLE as CORP3_5_1_,
        employee3_.DEPT_CODE as DEPT13_5_1_,
        employee3_.E_MAIL as E4_5_1_,
        employee3_.EMP_FIRST_NAME as EMP5_5_1_,
        employee3_.HIRE_DATE as HIRE6_5_1_,
        employee3_.JOB_CODE as JOB7_5_1_,
        employee3_.JOB_TITLE_DESC as JOB8_5_1_,
        employee3_.EMP_LAST_NAME as EMP9_5_1_,
        employee3_.MANAGER_ID as MANAGER14_5_1_,
        employee3_.MANAGER_INDC as MANAGER10_5_1_,
        employee3_.EMP_MIDDLE_NAME as EMP11_5_1_ 
    from
        EMPLOYEE this_ 
    inner join
        PREFERENCE preference2_ 
            on this_.EMP_ID=preference2_.EMP_ID 
    left outer join
        EMPLOYEE employee3_ 
            on preference2_.UPDATED_BY=employee3_.EMP_ID
Hibernate: 
    select
        this_.EMP_ID as EMP1_5_2_,
        this_.ISACTIVE as ISACTIVE5_2_,
        this_.COMPANY_CODE as COMPANY12_5_2_,
        this_.CORP_TITLE as CORP3_5_2_,
        this_.DEPT_CODE as DEPT13_5_2_,
        this_.E_MAIL as E4_5_2_,
        this_.EMP_FIRST_NAME as EMP5_5_2_,
        this_.HIRE_DATE as HIRE6_5_2_,
        this_.JOB_CODE as JOB7_5_2_,
        this_.JOB_TITLE_DESC as JOB8_5_2_,
        this_.EMP_LAST_NAME as EMP9_5_2_,
        this_.MANAGER_ID as MANAGER14_5_2_,
        this_.MANAGER_INDC as MANAGER10_5_2_,
        this_.EMP_MIDDLE_NAME as EMP11_5_2_,
        preference2_.EMP_ID as EMP1_13_0_,
        preference2_.UPDATED_BY as UPDATED4_13_0_,
        preference2_.UPDATED_DATE as UPDATED2_13_0_,
        preference2_.LANGUAGE as LANGUAGE13_0_,
        employee3_.EMP_ID as EMP1_5_1_,
        employee3_.ISACTIVE as ISACTIVE5_1_,
        employee3_.COMPANY_CODE as COMPANY12_5_1_,
        employee3_.CORP_TITLE as CORP3_5_1_,
        employee3_.DEPT_CODE as DEPT13_5_1_,
        employee3_.E_MAIL as E4_5_1_,
        employee3_.EMP_FIRST_NAME as EMP5_5_1_,
        employee3_.HIRE_DATE as HIRE6_5_1_,
        employee3_.JOB_CODE as JOB7_5_1_,
        employee3_.JOB_TITLE_DESC as JOB8_5_1_,
        employee3_.EMP_LAST_NAME as EMP9_5_1_,
        employee3_.MANAGER_ID as MANAGER14_5_1_,
        employee3_.MANAGER_INDC as MANAGER10_5_1_,
        employee3_.EMP_MIDDLE_NAME as EMP11_5_1_ 
    from
        EMPLOYEE this_ 
    inner join
        PREFERENCE preference2_ 
            on this_.EMP_ID=preference2_.EMP_ID 
    left outer join
        EMPLOYEE employee3_ 
            on preference2_.UPDATED_BY=employee3_.EMP_ID

Answer 1

是否无法想象您实际上有零行用于连接查询？加入 PREFERENCE 是否成功？