java - 调用 getChoice() 方法时出现错误,我不知道为什么

标签 java

我在调用 getChoice() 方法时遇到错误,其变量 footballTeam2 已在 main 方法中定义,这是为什么呢?我也正确地调用了我的其他方法吗? 提前谢谢大家,真的需要一些帮助。

import java.util.Scanner;

public class FootballGame { 
    static Scanner keyboard = new Scanner(System.in);
    static int arewedone = 0;
    static String choice;
    static FootballTeam team;

public static void main(String[] args) {

    FootballTeam footballTeam1;
    FootballTeam footballTeam2;

    System.out.print("Enter a name for a team:");
    footballTeam1 = new FootballTeam(keyboard.nextLine(), 0);
    System.out.print("Enter a name for another team:");
    footballTeam2 = new FootballTeam(keyboard.nextLine(), 0);

    do{
        System.out.println("Game Score:");
        System.out.println(footballTeam1.getName() + ":" + footballTeam1.getScore());
        System.out.println(footballTeam2.getName() + ":" + footballTeam2.getScore());

        choice = getMenuChoice(FootballTeam footballTeam1, FootballTeam footballTeam2);
        handleTeamScore(team);

    }while(arewedone == 0);
}

public static String getMenuChoice(FootballTeam footballTeam1, FootballTeam footballTeam2) {
    String input;

    do {
        System.out.println("Select an option:");
        System.out.println("A:" + footballTeam1 + " scored");
        System.out.println("B:" + footballTeam2 + " scored");
        System.out.println("C: game ended.");
        System.out.println("?:");
        input = keyboard.nextLine();
        if (input.equalsIgnoreCase("A")) {
            choice = (footballTeam1 + "");
            arewedone = 0;
        } else if (input.equalsIgnoreCase("B")) {
            choice = (footballTeam2 + "");
            arewedone = 0;
        } else if (input.equalsIgnoreCase("C")) {
            System.out.println("Game Over");
            arewedone++;
        }

    } while (!input.equals("A") && !input.equals("B") && !input.equals("C"));

    return choice;
}

public static void handleTeamScore(FootballTeam team) {

    int points;

    do {
        System.out.println("How many points were scored?");
        System.out.print("?: ");

        points = keyboard.nextInt();

        if ((team.addScore(points)) == true) {
            arewedone++;
        } else {
            System.out.println("That was an invalid option. Please try again.");
            System.out.println("Hints:");
            System.out.println("Touchdown = 6 points");
            System.out.println("Field Goal = 3 points");
            System.out.println("Safety = 2 points");
            System.out.println("Extra Point = 1 point");
        }
    } while (arewedone == 0);
}    

这是我的另一个类,其中包含 addscore 方法以及 getter 和 setter。

public class FootballTeam {

private String name;
private int score;
public static int TOUCHDOWN = 6;
public static int FIELD_GOAL = 3;
public static int SAFETY = 2;
public static int TWO_POINT_CONVERSION = 2;
public static int EXTRA_POINT = 1;


public FootballTeam(String name, int score) {
    this.name = name;
    this.score = score;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public int getScore() {
    return score;
}

public void setScore(int score) {
    this.score = score;
}

public boolean addScore(int points) {
    if (points == TOUCHDOWN || points == FIELD_GOAL || points == SAFETY || points == TWO_POINT_CONVERSION || points == EXTRA_POINT) {
        score = points + score;
        return true;
    } else {
        return false;
    }

}
}

最佳答案

更改方法调用

choice = getMenuChoice(FootballTeam footballTeam1, FootballTeam footballTeam2);

为此:

choice = getMenuChoice(footballTeam1, footballTeam2);

编辑:

在调用handleTeamScore(team);之前需要初始化FootballTeam team:

team = new FootballTeam(...);
handleTeamScore(team);

更改 getMenuChoice 的代码块:

if (input.equalsIgnoreCase("A")) {
            choice = (footballTeam1 + "");
            arewedone = 0;
        } else if (input.equalsIgnoreCase("B")) {
            choice = (footballTeam2 + "");
            arewedone = 0;

为此:

public static String getMenuChoice(...){
...
if (input.equalsIgnoreCase("A")) {
            choice = "footballTeam1";
            arewedone = 0;
        } else if (input.equalsIgnoreCase("B")) {
            choice = "footballTeam2";
            arewedone = 0;
...
}

现在替换 main 中的这两个语句:

choice = getMenuChoice(footballTeam1, footballTeam2);
handleTeamScore(team);

为此:

choice = getMenuChoice(footballTeam1, footballTeam2);
if(choice != null) {
if(choice.equals("footballTeam1")){
team = footballTeam1;
}

if(choice.equals("footballTeam2")){
team = footballTeam2;
}
handleTeamScore(team);
}

关于java - 调用 getChoice() 方法时出现错误,我不知道为什么,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19872240/

相关文章:

Java包定义

java - 如何实现 FPS 相机?

java - 给定 int 的字符串表示,检查溢出

java - 从现有的 OutputStream 创建 Java-Zip-Archive

java - 创建 mysql docker 容器设置环境变量

java - Hibernate 中来自服务器的重复 key 或完整性约束违规消息

java - 为什么会陷入无限循环

java - 如何在 Tab 布局中设置 Tab 宽度?

java - 传承的微妙之处

java - 将 OpenIE 三元组转换为 N-三元组 (NT)