java - JTable setValueAt 不工作

Question

我正在玩国际象棋游戏，我需要制作一个打印每一步棋的日志表。 LogTable类是这样的:

public class LogTable {
    private DefaultTableModel model;
    private JTable table;
    public LogTable(JPanel panel){
        String[] columnNames = {"Move No.",
                                "White",
                                "Black"};

        model = new DefaultTableModel(columnNames, 0);
        table = new JTable();
        //model.isCellEditable(i, i1)
        table.setModel(model);

        table.setPreferredScrollableViewportSize(new Dimension(500, 70));
        table.setFillsViewportHeight(true);

        //Create the scroll pane and add the table to it.
        JScrollPane scrollPane = new JScrollPane(table);

        panel.add(scrollPane);
    }

    public void newMove(chessPiece piece){
        if (piece.getColor() == 0){
            Object[] newRow = new Object[3];
            newRow[0] = model.getRowCount()+1;
            newRow[1] = piece.sayPos();
            newRow[2] = " ";
            model.addRow(newRow);
        }
        else {
            model.setValueAt(piece.sayPos(), model.getRowCount(), model.getColumnCount());
        }
    }
}

但是在第一个黑棋中它抛出一个 ArrayOutOfBoundsException。 newMove 函数在 chessPiece 类中被调用:

public void move(int newX, int newY, JPanelSquare jPanelSquareGrid[][], LogTable logTable){
    resetShowValidMoves(jPanelSquareGrid);
    logTable.newMove(this);
}

其余的移动代码在每个片段中，调用 super.我正在使用 DefaultTableModel。

Answer 1

来自 Java API :

public DefaultTableModel(Object[] columnNames,int rowCount)

Constructs a DefaultTableModel with as many columns as there are elements in columnNames and rowCount of null object values. Each column's name will be taken from the columnNames array.

您用 0 行实例化 DefaultTableModel。因此，您无法设置第 0 行中某个项目的值，因为它不存在。