我用 java swing 写了一个框架。在里面我有一个复选框。我想要,在单击其他项目的复选框后将更改它的可见性。我试图按照下面的代码进行操作,但没有按我希望的那样工作。
public InFrm() {
setTitle("In");
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setBounds(100, 100, 450, 300);
getContentPane().setLayout(new GridLayout(1, 1, 0, 0));
seeMe=false;
JSplitPane splitPane = new JSplitPane();
splitPane.setResizeWeight(0.7);
splitPane.setOrientation(JSplitPane.VERTICAL_SPLIT);
getContentPane().add(splitPane);
JPanel panel = new JPanel();
splitPane.setLeftComponent(panel);
panel.setLayout(null);
JPanel panel_1 = new JPanel();
splitPane.setRightComponent(panel_1);
panel_1.setLayout(null);
JLabel lblKind= new JLabel("Kind");
lblKind.setBounds(10, 8, 33, 14);
lblKind.setVisible(seeMe);
panel_1.add(lblKind);
JComboBox ChoiceOd = new JComboBox();
ChoiceOd.setBounds(53, 5, 28, 20);
ChoiceOd.setVisible(seeMe);
panel_1.add(ChoiceOd);
// more items using seeMe
JCheckBox chckbxOd = new JCheckBox("Od");
chckbxOd.addItemListener(new ItemListener() {
public void itemStateChanged(ItemEvent e) {
seeOd();
}
});
chckbxOd.setBounds(6, 150, 97, 23);
panel.add(chckbxOd);
}
protected void seeOd() {
if(seeMe){
seeMe=false;
}
else
{
seeMe=true;
}
}
最佳答案
在您的 see 方法中,您只设置了标志,但当然它不会设置组件的可见性。将可见性直接设置为组件,它将起作用
关于java - 单击复选框时如何设置另一个项目可见?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35701228/