java - 匹配字符串之间的多个数字，处理并替换

Question

我有一个包含多个数字的字符串，这些数字必须再次处理并替换为同一个字符串。

例如:

假设我有:

my name is anusha, I am a noob in Java having reputation: 3647 haha I am just kidding my actual reputation is 0001

现在假设我想提取 3647 并对其进行乘法、除法或加法运算。让我们除以 3647/100 = 36.47 并用与 0001 相同的字符串中的原始数字替换并替换为 00.01。

结果字符串应该是:

my name is anusha, I am a noob in Java having reputation: 36.47 haha I am just kidding my actual reputation is 00.01

感谢您的帮助。我知道这对很多人来说很愚蠢，但我仍在学习。

我试过:

Pattern intsOnly = Pattern.compile("\\d+");
    Matcher makeMatch = intsOnly.matcher("my name is anusha, I am a noob in Java having reputation: 3647 haha I am just kidding my actual reputation is 0001");
    makeMatch.find();
    String inputInt = makeMatch.group();
    System.out.println(inputInt);

但显然它只获取第一个数字，因为我没有使用循环，而且我也不确定如何处理该数字。

Answer 1

试试这个:

    final String regex = "\\d+";
    String string = "my name is anusha, I am a noob in Java having reputation: 3647 haha I am just kidding my actual reputation is 0001";
    NumberFormat formatter = new DecimalFormat("00.00");     

    final Pattern pattern = Pattern.compile(regex);
    final Matcher matcher = pattern.matcher(string);

    while (matcher.find()) {
        Float val=new Float(matcher.group(0));
        val=val/100;
        string=string.replace(matcher.group(0),formatter.format(val));
    }
    System.out.println(string);

}

输出:

my name is anusha, I am a noob in Java having reputation: 36.47 haha I am just kidding my actual reputation is 00.01