ios - 如何找出触摸事件在哪个 View 结束？

Question

我希望将 UIImage 拖到多个 UIButton 之一上，并根据我将其拖到的按钮重新定位。

我遇到的问题是 UITouch 只记录我的触摸开始的 View ，我想访问我的触摸结束的 View 。我该怎么做？

代码:

-(void) touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
    UITouch *touch = [touches anyObject];
    CGPoint location = [touch locationInView:self.view];

    dealerBtnOrigin = [touch locationInView:self.view];

    //NSLog(@"%u %u",touch.view.tag, ((UIView *)[dealerBtns objectAtIndex:[table getButtonSeat]]).tag);
    //CHECK TO SEE WHICH BUTTON WAS TOUCHED
    if (touch.view == ((UIView *)[dealerBtns objectAtIndex:[table getButtonSeat]]))
    {
        ((UIView *)[dealerBtns objectAtIndex:[table getButtonSeat]]).center = location;
    }
}

-(void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event
{
    UITouch *touch = [touches anyObject];
    CGPoint location = [touch locationInView:self.view];


    if (touch.view == ((UIView *)[dealerBtns objectAtIndex:[table getButtonSeat]]))
    {
        ((UIView *)[dealerBtns objectAtIndex:[table getButtonSeat]]).center = location;
    }
}

-(void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{
    UITouch *touch = [touches anyObject];
    CGPoint location = [touch locationInView:self.view];
    UIView *endView = [self.view hitTest:location withEvent:nil];

    if (touch.view == ((UIView *)[dealerBtns objectAtIndex:[table getButtonSeat]]))
    {
        NSLog(@"%u %u",endView.tag, touch.view.tag);
        if([buttons containsObject:(UIButton *)endView])
        {
            [[dealerBtns objectAtIndex:[table getButtonSeat]] setHidden:YES];
            [table passButton:touch.view.tag];
            [[dealerBtns objectAtIndex: touch.view.tag] setHidden:NO];
        }
        ((UIView *)[dealerBtns objectAtIndex:[table getButtonSeat]]).center = dealerBtnOrigin;
    }

}

Answer 1

使用 HitTest 。根据最终 super View self.view，您知道该点的位置作为 CGPoint。然后你可以问self.view那个点在它的哪个 subview 中:

CGPoint location = [touch locationInView:self.view];
UIView* v = [self.view hitTest:location withEvent:nil];

UIView v 是您正在寻找的 View 。