我在 Eclipse Photon 上用 Java 8 编写了一个简单的 webService，使用 RestTemplate 发布(使用 postForObject)一个包装对象列表(称为 PatentDetails )的对象(称为 patentListWrapper)。我从 Java 客户端(称为 MainWsClient )发帖，然后在服务器端的 patentDetails 中设置一个值，并在客户端读取 patentListWrapper 对象。当服务器端(程序 SpringWebServiceHello)仅使用 1 个 jar 文件(Spring-web.5.07.RELEASE.jar)使用旧的 Spring MVC 4 技术时，它工作正常 - serverSideExample即控制访问点的 web.xml 和 rest-servlet.xml 文件。然后我使用带有 Spring 5.07 jar 的 SpringBoot 2.03 和 Maven 编写了另一个服务器端程序(PndGuidRequestWs)，具有相同的@RequestMapping 方法但没有 web.xml 文件和 application.properties 文件中定义的访问点:
server.port=8082
server.servlet.path=/
#spring.mvc.servlet.path=/
#server.servlet.contextPath=/
当我使用此客户端调用此新服务器程序时 - ARC它也很好用 但是当我使用相同的 java 客户端和完全相同的请求调用它时(显然接受不同的 url)。我收到 400 错误:
2018-12-18 16:56:53,861 [main] INFO - Running MainWsClient with name = DS fileType = post3
2018-12-18 16:56:54,101 [main] DEBUG - Created POST request for "http://localhost:8082/guidRequest/xmlList"
2018-12-18 16:56:54,145 [main] DEBUG - Setting request Accept header to [application/xml, text/xml, application/json, application/*+xml, application/*+json]
2018-12-18 16:56:54,152 [main] DEBUG - Writing [com.springservice.client.PatentListWrapper@4ba2ca36] using [org.springframework.http.converter.xml.Jaxb2RootElementHttpMessageConverter@3444d69d]
2018-12-18 16:56:54,384 [main] DEBUG - POST request for "http://localhost:8082/guidRequest/xmlList" resulted in 400 (null); invoking error handler
2018-12-18 16:56:54,387 [main] ERROR - DS1B org.springframework.web.client.HttpClientErrorException: 400 null
不工作的，PndGuidRequestWs，服务器端有:
@RestController
public class PndController {
@RequestMapping(value = "/guidRequest/xmlList", method = RequestMethod.POST, produces = { "application/xml" } )
public PatentListWrapper guidSearchList(@RequestBody PatentListWrapper patentListWrapper) {
for (PatentDetails pd : patentListWrapper.getPatentList())
{
pd.setGuid("guidSetOnServer3");
}
return patentListWrapper;
}
}
工作的(SpringWebServiceHello)服务器端是相同的，除了:
value = "/service/greeting/xml/post2"
Java 客户端有:
public void runCode(String name , String fileType)
{
String url;
if (fileType.equalsIgnoreCase("post2")) {
url = "http://localhost:8080/SpringWebServiceHello/service/greeting/xml/post2";
// This method is identicle to postToPndGuidRequestWs() but this method works fine.
postToSpringWebServiceHello(url);
}else if (fileType.equalsIgnoreCase("post3")) {
url = "http://localhost:8082/guidRequest/xmlList";
// This method gives 404 error
postToPndGuidRequestWs(url);
}
}
private void postToPndGuidRequestWs(String url)
{
PatentListWrapper patentListWrapper = new PatentListWrapper();
PatentDetails pd = new PatentDetails("CN","108552082","A","00000000",12345,"guidIn");
List<PatentDetails> patentList = new ArrayList<PatentDetails>();
patentList.add(pd);
patentListWrapper.setPatentList(patentList);
RestTemplate restTemplate = new RestTemplate();
/* HttpHeaders headers = new HttpHeaders();
headers.add("header_name", "header_value");
headers.setContentType(MediaType.APPLICATION_XML);
HttpEntity<PatentListWrapper> request = new HttpEntity<PatentListWrapper>(patentListWrapper, headers); */
/*List<HttpMessageConverter<?>> messageConverters = new ArrayList<HttpMessageConverter<?>>();
Jaxb2RootElementHttpMessageConverter jaxbMessageConverter = new Jaxb2RootElementHttpMessageConverter();
List<MediaType> mediaTypes = new ArrayList<MediaType>();
mediaTypes.add(MediaType.APPLICATION_XML);
jaxbMessageConverter.setSupportedMediaTypes(mediaTypes);
messageConverters.add(jaxbMessageConverter);
restTemplate.setMessageConverters(messageConverters);*/
/* headers = new HttpHeaders();
headers.setAccept(Collections.singletonList(MediaType.APPLICATION_XML));
HttpEntity<String> entity = new HttpEntity<>("parameters", headers);*/
try {
patentListWrapper = restTemplate.postForObject(
url,
patentListWrapper,
PatentListWrapper.class);
logger.debug("DS1A employee obj returned. guid = " + patentListWrapper.getPatentList().get(0).getGuid());
}catch(Exception e) {
logger.error("DS1B " + e);
}
}
即fileType="post2"调用SpringWebServiceHello，fileType="post3"调用PndGuidRequestWs。如您所见，我已经尝试了几个注释掉的解决方案，但没有任何效果。由于 2 个服务器端程序之间唯一真正的区别是，没有一个工作的程序使用 Spring 引导，而工作的程序不使用 SpringBoot 设置，即目录结构、application.properties 或 pom.xml。我的 pom.xml 有:
<?xml version="1.0" encoding="UTF-8"?>
http://maven.apache.org/xsd/maven-4.0.0.xsd"> 4.0.0
<groupId>com.clarivate</groupId>
<artifactId>pndguidrequestws</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>war</packaging>
<name>pndGuidRequestWs</name>
<description>Guid request webService</description>
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.0.3.RELEASE</version>
<relativePath/> <!-- lookup parent from repository -->
</parent>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding>
<java.version>1.8</java.version>
<start-class>com.clarivate.pndguidrequestws.PndGuidRequestWsApplication</start-class>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-tomcat</artifactId>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>com.oracle</groupId>
<artifactId>ojdbc6</artifactId>
<version>11.2.0.1.0</version>
<!-- <scope>provided</scope> --> <!-- DS insert for unix -->
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-jdbc</artifactId>
<exclusions>
<exclusion>
<groupId>org.apache.tomcat</groupId>
<artifactId>tomcat-jdbc</artifactId>
</exclusion>
</exclusions>
</dependency>
<!-- Implementing XML Representation for Spring Boot Services -->
<dependency>
<groupId>com.fasterxml.jackson.dataformat</groupId>
<artifactId>jackson-dataformat-xml</artifactId>
</dependency>
<!-- httpcomponents jars are Required by PndGuidGenerator -->
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpcore</artifactId>
</dependency>
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpclient</artifactId>
</dependency>
</dependencies>
<build>
<finalName>PndGuidRequestWs</finalName>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
<configuration>
<executable>true</executable>
</configuration>
</plugin>
</plugins>
</build>
</project>
PatentListWrapper 类是:
package com.clarivate.pndguidrequestws.model;
import java.util.List;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class PatentListWrapper {
private List<PatentDetails> patentList;
public PatentListWrapper() {}
public List<PatentDetails> getPatentList() {
return patentList;
}
public void setPatentList(List<PatentDetails> patentList) {
this.patentList = patentList;
}
}
欢迎提出任何建议。
编辑: 为了简化对象，我创建了仅包含 1 个字符串成员的 PatentListWrapper2:
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class PatentListWrapper2 {
private String name;
public PatentListWrapper2() {}
public PatentListWrapper2(String name) {
this.name = name;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
我可以再次使用 ARC 客户端成功发送此 xml:
<patentListWrapper2>
<name>DSDS</name>
</patentListWrapper2>
contentType="application/xml" 但是当我尝试从 java 发送 patentListWrapper2 时，我收到一个解码错误:
2018-12-20 09:17:13,931 [main] INFO - Running MainWsClient with name = DS fileType = post4
2018-12-20 09:17:14,166 [main] DEBUG - Created POST request for "http://localhost:8082/guidRequest/xmlList2"
2018-12-20 09:17:14,200 [main] DEBUG - Setting request Accept header to [application/xml, text/xml, application/json, application/*+xml, application/*+json]
2018-12-20 09:17:14,206 [main] DEBUG - Writing [com.springservice.client.PatentListWrapper2@517cd4b] using [org.springframework.http.converter.xml.Jaxb2RootElementHttpMessageConverter@6cc7b4de]
2018-12-20 09:17:14,246 [main] DEBUG - POST request for "http://localhost:8082/guidRequest/xmlList2" resulted in 200 (null)
2018-12-20 09:17:14,248 [main] DEBUG - Reading [com.springservice.client.PatentListWrapper2] as "application/xml;charset=UTF-8" using [org.springframework.http.converter.xml.Jaxb2RootElementHttpMessageConverter@6cc7b4de]
2018-12-20 09:17:14,255 [main] ERROR - DS2B org.springframework.web.client.RestClientException: Error while extracting response for type [class com.springservice.client.PatentListWrapper2] and content type [application/xml;charset=UTF-8]; nested exception is org.springframework.http.converter.HttpMessageNotReadableException: Could not unmarshal to [class com.springservice.client.PatentListWrapper2]: unexpected element (uri:"", local:"PatentListWrapper2"). Expected elements are <{}patentListWrapper2>; nested exception is javax.xml.bind.UnmarshalException: unexpected element (uri:"", local:"PatentListWrapper2"). Expected elements are <{}patentListWrapper2>
EDIT2 我在 Eclipse Tomcat 上运行 pndGuidRequestWs，而不是 - Run As -> Spring Boot App。服务器日志如下:
2018-12-20 11:15:45.655 WARN 236 --- [nio-8080-exec-6] .w.s.m.s.DefaultHandlerExceptionResolver : Failed to read HTTP message: org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot construct instance of `com.clarivate.pndguidrequestws.model.PatentDetails` (although at least one Creator exists): no String-argument constructor/factory method to deserialize from String value ('CN'); nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot construct instance of `com.clarivate.pndguidrequestws.model.PatentDetails` (although at least one Creator exists): no String-argument constructor/factory method to deserialize from String value ('CN') at [Source: (PushbackInputStream); line: 1, column: 98] (through reference chain: com.clarivate.pndguidrequestws.model.PatentListWrapper["patentList"]->java.util.ArrayList[0])
最佳答案
你能测试吗:
try {
HttpHeaders headers = new HttpHeaders();
//headers.setAccept(Arrays.asList(MediaType.APPLICATION_JSON));
//headers.setContentType((MediaType.APPLICATION_JSON));
// I comment the code abouve because you did not specify a consumes whitch defines the media types that the methods of
//a resource class or MessageBodyReader can accept. If not specified, a container will assume that any media type is acceptable.
HttpEntity<PatentListWrapper> request = new HttpEntity<>(patentListWrapper, headers);
PatentListWrapper patentListWrapperResult = = restTemplate.exchange(url, HttpMethod.POST, request,PatentListWrapper.class);
logger.debug("DS1A employee obj returned. guid = " + patentListWrapper.getPatentList().get(0).getGuid());
}catch(Exception e) {
logger.error("DS1B " + e);
}
关于java - Spring boot RestTemplate 发布 400 错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/53851279/