java - 我如何在java中将多个xml合并为单个xml

Question

考虑到我有 2 个具有相同结构但没有 dtd 的 xml 文件

xml1:

<DigestType name="Blogs">
<From>xxx@xx.org</FromEmail>
<EmailTimeStamp></EmailTimeStamp>
<EmailSubject></EmailSubject>
<BlogName href="">Merging XML</BlogName>
<Blog Count="2">
<listPost>
    <Title href="">Title</Title>
    <CommentCount>10</CommentCount>
    <Content>Post content...</Content>
</listBlogPost>
<listPost>
    <Title href="">Title1</Title>
    <CommentCount>10</CommentCount>
    <Content>Post content...</Content>
</listBlogPost>
</Blog>
</DigestType>

xml2:

<DigestType name="Blogs">
<From>xxx@xx.org</FromEmail>
<EmailTimeStamp></EmailTimeStamp>
<EmailSubject></EmailSubject>
<BlogName href="">Merging XML</BlogName>
<Blog Count="2">
        <listPost>
    <Title href="">Title2</Title>
    <CommentCount>1</CommentCount>
    <Content>content...</Content>
</listBlogPost>
<listPost>
    <Title href="">Title3</Title>
    <CommentCount>23</CommentCount>
    <Content>content...</Content>
</listBlogPost>
</Blog>

现在我想将这两个 xml 合并为一个

<DigestType name="Blogs">
<From>xxx@xx.org</FromEmail>
<EmailTimeStamp></EmailTimeStamp>
<EmailSubject></EmailSubject>
<BlogName href="">Merging XML</BlogName>
<Blog Count="4">
     <listPost>
    <Title href="">Title</Title>
    <CommentCount>10</CommentCount>
    <Content>Post content...</Content>
</listBlogPost>
<listPost>
    <Title href="">Title1</Title>
    <CommentCount>10</CommentCount>
    <Content>Post content...</Content>
</listBlogPost>


<listPost>
    <Title href="">Title2</Title>
    <CommentCount>1</CommentCount>
    <Content>content...</Content>
</listBlogPost>
<listPost>
    <Title href="">Title3</Title>
    <CommentCount>23</CommentCount>
    <Content>content...</Content>
</listBlogPost>
</Blog>
</DigestType>

我正在使用 java。谁能帮我找出解决办法。

谢谢 乌玛

Answer 1

使用 XPath :

XPath xpath = XPathFactory.newInstance().newXPath();
// load
Document xml1 = (Document) xpath.evaluate("/", new InputSource("xml1.xml"),
    XPathConstants.NODE);
NodeList listPosts = (NodeList) xpath.evaluate("/DigestType/Blog/listPost",
    new InputSource("xml2.xml"), XPathConstants.NODESET);
// merge
Element blog = (Element) xpath.evaluate("/DigestType/Blog", xml1,
    XPathConstants.NODE);
for (int i = 0; i < listPosts.getLength(); i++) {
  Node listPost = listPosts.item(i);
  blog.appendChild(xml1.adoptNode(listPost));
}
// set count
blog.setAttribute("Count", xpath.evaluate("count(listPost)", blog));
// print
DOMImplementationLS impl = (DOMImplementationLS) xml1.getImplementation();
System.out.println(impl.createLSSerializer().writeToString(xml1));

(您的 XML 格式不正确；我假设元素开始的名称是正确的。)