我正在开发 iOS 聊天客户端。谁能帮我解决多用户聊天问题?
我已经实现了 Robbiehanson 的 XMPPFramework。
谁能告诉我如何使用此框架获取组列表并在服务器中创建组?
提前致谢。
最佳答案
获取房间列表:
NSString* server = @"chat.shakespeare.lit"; //or whatever the server address for muc is
XMPPJID *servrJID = [XMPPJID jidWithString:server];
XMPPIQ *iq = [XMPPIQ iqWithType:@"get" to:servJID];
[iq addAttributeWithName:@"from" stringValue:[xmppStream myJID].full];
NSXMLElement *query = [NSXMLElement elementWithName:@"query"];
[query addAttributeWithName:@"xmlns" stringValue:@"http://jabber.org/protocol/disco#items"];
[iq addChild:query];
[xmppStream sendElement:iq];
检查委托(delegate)方法中的响应:
- (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq{
DDLogVerbose(@"%@", [iq description]);
return NO;
}
加入或创建房间
XMPPRoomMemoryStorage * _roomMemory = [[XMPPRoomMemoryStorage alloc]init];
NSString* roomID = @"roomExample@chat.shakespeare.lit";
XMPPJID * roomJID = [XMPPJID jidWithString:roomID];
XMPPRoom* xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:_roomMemory
jid:roomJID
dispatchQueue:dispatch_get_main_queue()];
[xmppRoom activate:self.xmppStream];
[xmppRoom addDelegate:self delegateQueue:dispatch_get_main_queue()];
[xmppRoom joinRoomUsingNickname:@"myNickname"
history:nil
password:nil];
检查 XMPPRoom 委托(delegate)方法中的响应:
- (void)xmppRoomDidCreate:(XMPPRoom *)sender{
DDLogVerbose(@"%@: %@", THIS_FILE, THIS_METHOD);
}
- (void)xmppRoomDidJoin:(XMPPRoom *)sender{
DDLogVerbose(@"%@: %@", THIS_FILE, THIS_METHOD);
}
更新
配置房间:
之后:
[xmppRoom joinRoomUsingNickname:self.xmppStream.myJID.user
history:history
password:nil];
添加:
[xmppRoom fetchConfigurationForm];
并检查响应:
- (void)xmppRoom:(XMPPRoom *)sender didFetchConfigurationForm:(NSXMLElement *)configForm{
DDLogVerbose(@"%@: %@ -> %@", THIS_FILE, THIS_METHOD, sender.roomJID.user);
}
查看 configForm
对象,并根据需要进行更改,然后使用 [sender configureRoomUsingOptions:newConfig];
发送它
示例: 要更改配置以使房间持久化,您可以添加如下内容:
NSXMLElement *newConfig = [configForm copy];
NSArray* fields = [newConfig elementsForName:@"field"];
for (NSXMLElement *field in fields) {
NSString *var = [field attributeStringValueForName:@"var"];
if ([var isEqualToString:@"muc#roomconfig_persistentroom"]) {
[field removeChildAtIndex:0];
[field addChild:[NSXMLElement elementWithName:@"value" stringValue:@"1"]];
}
}
[sender configureRoomUsingOptions:newConfig];
(我不熟悉 NSXMLElement,所以也许有更好的方法来更改值)
关于ios - XMPPFramework - 实现群聊 (MUC),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19268629/