java - @ExceptionHandler 仅适用于 Exception.class

Question

我在我的一个 Controller 上使用 @ExceptionHandler 注释，但是如果我使用 Exception.class 之外的任何异常类型，页面将返回消息

The request sent by the client was syntactically incorrect.

这是我的 Controller :

@Controller
@RequestMapping("/foobar")
public class TodayInHistoryController {

@Autowired(required = true)
private TodayInHistoryService service;

private static final String DATE_FMT = "yyyyMMdd";

/**
 * 
 * @return
 */
@RequestMapping(method = RequestMethod.GET)
public HistoryContent getTodayInHistory(
    @RequestParam(value = "date", required = false) Date date) {
if (date != null)
    return service.getHistoryContent(date);

return service.getHistoryContent();
}

/**
 * Binds URL arguments to their correct object representation.
 * 
 * @param binder
 */
@InitBinder
public void initBinder(WebDataBinder binder) {
// Date object binder
SimpleDateFormat dateFormat = new SimpleDateFormat(DATE_FMT);
binder.registerCustomEditor(Date.class, new CustomDateEditor(
    dateFormat, false));
}

/**
 * 
 * @return
 */

// If I change the value param of the annotation to Exception.class it works fine...
@ExceptionHandler(NumberFormatException.class)
public ModelAndView handleParseException(Exception ex) {
    // create and populate Map to hold error data
Map<String, String> errorData = new HashMap<String, String>();
errorData.put("errorMessage","Formatting error occurred");
errorData.put("errorDetails", "None");

// create and return ModelAndView
ModelAndView mv = new ModelAndView();
mv.addAllObjects(errorData);

    return mv;
}
}

这是我的 spring 配置(相关的)

@Configuration
@Import(ServicesConfig.class)
@ImportResource({ "classpath:applicationContext-security.xml",
"classpath:dataSources.xml" })
@EnableWebMvc
@ComponentScan(basePackages = "my.controller")
public class WebConfig {

@Bean
public ViewResolver contentNegotiatingViewResolver() {
ContentNegotiatingViewResolver resolver = new ContentNegotiatingViewResolver();
resolver.setIgnoreAcceptHeader(true);
resolver.setDefaultContentType(MediaType.APPLICATION_JSON);
resolver.setFavorPathExtension(true);
resolver.setOrder(1);

// setup mediaTypes
Map<String, String> mediaTypes = new HashMap<String, String>();
mediaTypes.put("json", "application/json");
mediaTypes.put("xml", "application/xml");
resolver.setMediaTypes(mediaTypes);

// setup defaultViews
List<View> defaultViews = new ArrayList<View>();
defaultViews.add(jsonView());
defaultViews.add(xmlView());
resolver.setDefaultViews(defaultViews);

return resolver;
}

@Bean
public View jsonView() {
return new MappingJacksonJsonView();
}

@Bean
public View xmlView() {
return new MarshallingView(new CastorMarshaller());
}
}

Answer 1

这里的问题是 spring 尝试将日期字符串转换为 Date 并失败。发生这种情况时，会抛出 TypeMismatchException (它包装 IllegalArgumentException，而 IllegalArgumentException 又包装 ParseException)，您应该处理它，而不是 NumberFormatException.

当您将异常类更改为 Exception 时，它会得到处理，因为 TypeMismatchException 扩展了 Exception。

提示:如果您正在使用任何日志记录框架，请尝试为 spring mvc 类打开调试日志记录，它可以让事情变得更加清晰。

例如，在您的 lo4j.propeties 中添加类似的内容:

log4j.logger.org.springframework.servlet=DEBUG