我想创建一个在启动应用程序时打开的 Activity ,等待一段时间并跳转到下一个 Activity ,而无需用户按任何操作。
这是我的代码:
public class MainActivity extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Thread thread = new Thread();
thread.start();
}
public class waitSeconds extends Thread {
public void run() {
Log.i("MyActivity", "MyClass");
try {
wait(300);
Intent intent = new Intent(MainActivity.this, main_window.class);
startActivity(intent);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
因为它似乎永远不会进入“run”方法。
我该怎么做?
最佳答案
将其包含在您的 Activity 中:
public class MainActivity extends Activity{
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
SplashHandler handler=new SplashHandler();
Message msg = new Message();
msg.what = 0;
handler.sendMessageDelayed(msg, 3000);
}
private class SplashHandler extends Handler {
public void handleMessage(Message msg)
{
switch (msg.what)
{
default:
case 0:
super.handleMessage(msg);
Intent intent = new Intent(MainActivity.this,main_window.class);
startActivity(intent);
MainActivity.this.finish();
}
}
}
关于java - 在 Android 中,如何让 Activity 在跳到下一个 Activity 之前等待?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11500071/