java - 这将是解析以下日志文​​件的 java 正则表达式

Question

我需要用java解析日志文件。日志文件包含有关调用事务的信息。我感兴趣的行以及其中的信息在日志行条目示例中以粗体标记。对于以下一个，我需要提取状态和电话号码:

Aug 15 20:35:22 GMT 2012 tropo109.orl.voxeo.net TROPO 138595 0 e467547d3333724bdd52635bbb713e77 1 d607eb64fb3bfbfd273a55f4b121b903 SimpleOutgoingCall[+17877058826/null->+17877260664/null] : [TRANSFER,*+17877260664*]

从这一行我需要获取电话号码和总通话时间。

Aug 15 20:35:22 GMT 2012 tropo109.orl.voxeo.net TROPO 138595 0 e467547d3333724bdd52635bbb713e77 1 d607eb64fb3bfbfd273a55f4b121b903 Logging CDR {"call":{"SipSessionID":"ss_jzto5yd4jruv","SessionID":"e467547d3333724bdd52635bbb713e77","CallID":"d607eb64fb3bfbfd273a55f4b121b903","ParentSessionID":"none","ParentCallID":"none","DateCreated":"Wed, 15 Aug 2012 20:34:14 +0000","DateUpdated":"Wed, 15 Aug 2012 20:34:14 +0000","AccountID":"138595","Called":"+17877260664","Caller":"+17877058826","PhoneNumberSid":"unknown","Disposition":"Script ended","Status":"Success","StartTime":"Wed, 15 Aug 2012 20:34:14 +0000","EndTime":"Wed, 15 Aug 2012 20:35:22 +0000","Duration":"67950","Flags":"out","RecordingDuration":"0","Network":"SIP","Channel":"VOICE","ApplicationId":"392671","ApplicationType":"groovy","ServiceId":"1291899","StartUrl":"http://hosting.tropo.com/138595/www/outboud-web2ivr.groovy","BrowserIP":"10.6.69.109","PPID":"461"}}

因此，一般来说，我需要解析文件并在不同的日志行条目中获取调用状态和持续时间。有什么指点吗？

更新: 我得到了获取第一部分的代码，任何关于如何获取第二部分的指针，并且只有一个编译表达式，可以在日志输入行中找到(电话，状态)或(电话，通话持续时间)？:

private static void matchParts( String aText ){

  Pattern pattern = Pattern.compile("(?:\\[(\\w(\\w)*),(\\+\\d{11})\\])");
  Matcher matcher = pattern.matcher(aText );
  String phone;
      String status;
  while (matcher.find()) {
         System.out.println("phone:" +matcher.group(3) + ", status: "+matcher.group(1) );
  }

}

Answer 1

对于第一个:

private static void matchParts(String line){
   Pattern pattern = Pattern.compile(": \\[(\\w+),\\*(\\+\\d{11})\\*]");
   Matcher matcher = pattern.matcher(line);
   String phone;
   String status;
   while (matcher.find()) {
      System.out.println("phone:" +matcher.group(2) + ", status: "+matcher.group(1) );
   }
}

对于第二个:

private static void matchParts(String line){
   Pattern pattern = Pattern.compile("Called\":\"(\\+\\d{11}).*\"Duration\":\"(\\d+)");
   Matcher matcher = pattern.matcher(line);
   String phone;
   String status;
   while (matcher.find()) {
      System.out.println("phone:" +matcher.group(1) + ", duration: "+matcher.group(2) );
   }
}

我使用这个非常方便的工具:http://www.regexplanet.com/advanced/java/index.html当涉及到查找正则表达式时。

编辑: 如果您正在寻找 1 个正则表达式，它可能是这样的:

Pattern.compile("\\[(\\w+),\\*(\\+\\d{11})\\*].*?Called\":\"(\\+\\d{11}).*?\"Duration\":\"(\\d+)", Pattern.MULTILINE);