java - Click 和 LongClick 监听器抛出 IllegalStateException

Question

尝试为 RelativeLayout 实现 onClickListener 和 onLongClickListener 时出现此错误:

10-19 17:49:31.400: E/AndroidRuntime(30886): FATAL EXCEPTION: main
10-19 17:49:31.400: E/AndroidRuntime(30886): java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

这是代码的一部分:

RelativeLayout meals_layout = (RelativeLayout) view
.findViewById(R.id.meals);      

meals_layout.setOnLongClickListener(new OnLongClickListener() { 
    @Override
    public boolean onLongClick(View v) {

        AlertDialog.Builder builder = new AlertDialog.Builder(
                JournalActivity.this);
        builder.setTitle(R.string.meal_delete); 
        builder.setView(clickView);

        builder.setPositiveButton(R.string.string_delete,
                new DialogInterface.OnClickListener() {

            @Override
            public void onClick(DialogInterface dialog, int which) {

            }

        });
        builder.setNegativeButton(R.string.string_cancel,
                new DialogInterface.OnClickListener() {

            @Override
            public void onClick(DialogInterface dialog,
                    int which) {
                // Do nothing
                dialog.dismiss();
            }
        });

        builder.create().show();
        return false;
    }
});

meals_layout.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View v) {
        AlertDialog.Builder builder = new AlertDialog.Builder(
                JournalActivity.this);
        builder.setTitle(R.string.meal_edit); // al que hacerlo bonito
        builder.setView(clickView);

        builder.setPositiveButton(R.string.string_edit,
                new DialogInterface.OnClickListener() {
        }
    });

        builder.setNegativeButton(R.string.string_cancel,
                new DialogInterface.OnClickListener() {

            @Override
            public void onClick(DialogInterface dialog,
                    int which) {
                // Do nothing
                dialog.dismiss();
            }
        });


        builder.create().show();

}
});

第一次打开 Activity 时，我可以根据需要多次长按。但是，当我单击任何其他按钮(不仅是此处判决的按钮)时，如果我再次尝试长按...应用程序就会崩溃。

我将非常感谢您的帮助。 谢谢:)

Answer 1

每个 View 仅允许一个父 View 。显然 clickView 已经有一个，所以当你调用 setView(clickView) 时它会抛出错误。一种修复方法是添加:

((GroupView) clickView.getParent()).removeView(clickView);

到两位听众的开头。这将“孤立”clickView，以便将其添加到 AlertDialog。