我正在使用 11 g Express 版本、Eclipse Juno、Java 6
Oracle 已启动并正在运行,甚至尝试立即关闭并启动,但没有收到 SID 监听器错误
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="default" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>com.crspdemo.Employee</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:oracle:thin:@localhost:1521:jsfDatabase"/>
<property name="javax.persistence.jdbc.password" value="admin"/>
<property name="javax.persistence.jdbc.driver" value="oracle.jdbc.driver.OracleDriver"/>
<property name="javax.persistence.jdbc.user" value="system"/>
<!--<property name="eclipselink.ddl-generation" value="create-tables"/>-->
</properties>
</persistence-unit>
</persistence>
错误:
Caused by: javax.persistence.PersistenceException: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.2.0.v20110202-r8913): org.eclipse.persistence.exceptions.DatabaseException
内部异常:java.sql.SQLException:监听器拒绝连接并出现以下错误: ORA-12505,TNS:监听器当前不知道连接描述符中给出的 SID
Listner.ora
最佳答案
尝试使用 XE 的默认 SID:
<property name="javax.persistence.jdbc.url" value="jdbc:oracle:thin:@localhost:1521:XE"/>
关于java - 持久性、oracle Thin、ORA-12505、TNS 监听器当前不知道 SID,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14662631/