问题: 我如何从数组中查找最小值/最大值以及语法是什么样的?
((编辑:开始研究它可能的样子(在这篇文章的底部),但我没有得到正确的语法))
想在我的主课中创建一个方法,从一组学生中找到成绩最好和最差的学生(并打印),不确定数组的语法如何。
Main.java
import java.util.*;
import java.io.*;
public class Main
{
private static int i=0;
public static void main (String[] args) throws IOException
{
Student[] arrStudents = new Student[7];
Scanner fileInput = new Scanner(new File("students.txt"));
while (fileInput.hasNext())
{
String firstName = fileInput.next();
String lastName = fileInput.next();
int grade = fileInput.nextInt();
arrStudents[i] = new Student(firstName, lastName, grade);
i++;
}
getExcellentStudents(arrStudents);
getOKStudents(arrStudents);
getFailStudents(arrStudents);
System.out.println();
System.out.println("Total Number of Students: " + arrStudents.length);
}
public static void getExcellentStudents(Student[] arrStudents) throws IOException {
System.out.println("Excellent Students: ");
for(int i = 0; i < arrStudents.length; i++) {
int grade = arrStudents[i].getGrade();
if (grade > 89) {
System.out.println(arrStudents[i]);
}
}
System.out.println();
}
public static void getOKStudents(Student[] arrStudents) throws IOException {
System.out.println("OK Students: ");
for(int i = 0; i < arrStudents.length; i++) {
int grade = arrStudents[i].getGrade();
if (grade > 60 && grade < 90) {
System.out.println(arrStudents[i]);
}
}
System.out.println();
}
public static void getFailStudents(Student[] arrStudents) throws IOException {
System.out.println("Failure Students: ");
for(int i = 0; i < arrStudents.length; i++) {
int grade = arrStudents[i].getGrade();
if (grade < 61) {
System.out.println(arrStudents[i]);
}
}
System.out.println();
}
Student.java
public class Student {
private String firstName, lastName;
private int grade;
public Student (String firstName, String lastName, int grade)
{
this.firstName = firstName;
this.lastName = lastName;
this.grade = grade;
}
public String toString()
{
return firstName + " " + lastName + " " + grade;
}
public int getGrade()
{
return grade;
}
}
学生.txt
John Smith 90
Barack Obama 95
Al Clark 80
Sue Taylor 55
Ann Miller 75
George Bush 58
John Miller 65
输出应如下所示(所以我现在缺少最后两行):
Excellent Students:
John Smith 90
Barack Obama 95
OK Students:
Al Clark 80
Ann Miller 75
John Miller 65
Failure Students:
Sue Taylor 55
George Bush 58
Total Number of Students: 7
Student With Highest Grade: Barack Obama 95
Student With Lowest Grade: Sue Taylor 55
在这里编辑比在评论中发布更容易。我更新了这篇文章,使其更清楚地表达了我的要求。
这是迄今为止我找到最大值的方法,但我仍然对到底什么去了哪里感到困惑。
public void outputMaxMin(Student[] arrStudents) throws IOException {
Student bestStudent;
Student worstStudent;
student = new Student();
for (int i = 0; i < arrStudents.length; i++) {
int grade = arrStudents[i].getGrade();
if (bestStudent == null && worstStudent == null) {
bestStudent = student;
worstStudent = student;
continue;
}
if (grade > bestStudent.grade){
bestStudent = student;
}
if (grade < worstStudent.grade){
worstStudent = student;
}
}
}
最佳答案
以下怎么样:
// assume students.length > 0
static void printMinMax(Student[] students) {
Student min = students[0];
Student max = students[0];
for (Student student: students) {
if (student.getGrade() > max.getGrade())
max = student;
if (student.getGrade() < min.getGrade())
min = student;
}
System.out.println("Best student: " + max);
System.out.println("Worst student: "+ min);
}
另一方面,您应该真正考虑使用集合而不是普通数组。 特别是因为您事先并不真正知道学生的数量。
上面的代码可以这样重写:
static void printMinMax(List<Student> students) {
Comparator<Student> comparator = new Comparator<>() {
@Override public int compare(Student s1, Student s2) {
return s1.getGrade() - s2.getGrade();
}
};
Student max = Collections.max(students, comparator);
Student min = Collections.min(students, comparator);
// print stuff
}
使用 java 8 lambda 或更短:
static void printMinMax(List<Student> students) {
Comparator<Student> comparator = (s1, s2) -> s1.getGrade() - s2.getGrade();
Student max = Collections.max(students, comparator);
Student min = Collections.min(students, comparator);
// print stuff
}
关于Java - 使用数组查找/打印最小值/最大值?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23550817/