java - 如何查看这个序列化的xml内容？

Question

当我向我的应用程序发送我感兴趣的特定远程查询时，我会拉回一个如下所示的 xml 文档:

<content>
    <id>694</id>
    <serializedContent>
        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
    </serializedContent>
</content>

来自该工具有关查询的文档:

[GET] /task/{taskId}/content
Gets the task content from a task identified by the given task id
Returns a JaxbContent with the content of the task. The taskId component of the URL must conform to the following regex: [0-9]+

我想知道的是:我在“serializedContent”标签中到底看到了什么，以及如何对其进行反序列化？

Answer 1

序列化的内容最像base6Binary，如果您自己处理它，您可以使用DatatypeConverter类，如下所示:

byte[] binary = DatatypeConverter.parseBase64Binary(string);

如果您想将其映射到 JAXB，您可以使用以下类来实现:

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Content {

    private int id;

    private byte[] serializedContent;

}