java - java中用空格替换回车符

Question

我在 java 中的字符串变量中有以下字符串。

rule "6"
no-loop true
    when
    then
    String prefix = null;
    prefix = "900";
    String style = null;
    style = "490";
    String  grade = null;
    grade = "GL";
    double basePrice = 0.0;
    basePrice = 837.00;
    String ruleName = null;
    ruleName = "SIVM_BASE_PRICE_006
Rahul Kumar Singh";
    ProductConfigurationCreator.createFact(drools, prefix, style,grade,baseprice,rulename);
end
rule "5"
no-loop true
    when
    then
    String prefix = null;
    prefix = "800";
    String style = null;
    style = "481";
    String  grade = null;
    grade = "FL";
    double basePrice = 0.0;
    basePrice = 882.00;
    String ruleName = null;
    ruleName = "SIVM_BASE_PRICE_005";
    ProductConfigurationCreator.createFact(drools, prefix, style,grade,baseprice,rulename);
end

我需要用空格替换“THEN”和“END”关键字之间的回车符，使其变得像下面的代码:

rule "6"
no-loop true
    when
    then
    String prefix = null;
    prefix = "900";
    String style = null;
    style = "490";
    String  grade = null;
    grade = "GL";
    double basePrice = 0.0;
    basePrice = 837.00;
    String ruleName = null;
    ruleName = "SIVM_BASE_PRICE_006 Rahul Kumar Singh";
    ProductConfigurationCreator.createFact(drools, prefix, style,grade,baseprice,rulename);
end

rule "5"
no-loop true
    when
    then
    String prefix = null;
    prefix = "800";
    String style = null;
    style = "481";
    String  grade = null;
    grade = "FL";
    double basePrice = 0.0;
    basePrice = 882.00;
    String ruleName = null;
    ruleName = "SIVM_BASE_PRICE_005";
    ProductConfigurationCreator.createFact(drools, prefix, style,grade,baseprice,rulename);
end

在上面的两个字符串集示例中，第二个是我需要的正确格式。然而，在第一组中，我得到了这个:

ruleName = "SIVM_BASE_PRICE_006
Rahul Kumar Singh";

具体需要是这样的:

ruleName = "SIVM_BASE_PRICE_006 Rahul Kumar Singh";

而且我还需要确保这不会影响字符串中的任何其他内容。 因此，我需要将这个“回车符”替换为空格并排成一行。这是我的要求。我尝试使用字符串的replace和replaceAll方法，但无法正常工作。

问题:

I need to look in between string "then" and "end" and in that whenever there is any carriage return in between two double quaotes "" ""; I need to replace this carriage return with white space and make it in one line.

谢谢

编辑:

DRT:

template header
Prefix
Style
Product

package com.xx
import com.xx.drools.ProductConfigurationCreator;

template "ProductSetUp"
rule "Product_@{row.rowNumber}"
no-loop true
    when
    then
      String prefix = null;
      prefix = "@{Prefix}";
      String style = null;
      prefix = "@{Style}";
      String product = null;
      product = "@{Product}";
      ProductConfigurationCreator.createProductFact(drools,prefix,style,product);
end
end template

excel和drt仅用于演示目的。 在图像中的“产品”列中，有“SOFAS\rkumar shorav”。实际上这是造成问题的。这将生成如下所示:

product = "SOFAS
kumar shorav";

我需要如下所示:

product = "SOFAS kumar shorav";

然后是 Excel 数据:

附图。

Answer 1

我可能会编写自己的格式化程序，而不是正则表达式

• 检查光标是否在引号内
• 将每个 \r 替换为空格
• 将每个 \n 替换为空格，除非它紧接在 \r 之后，这意味着已经为该 \r 放置了空格
• 写出其余字符，保持不变。

唯一可能的问题是，此格式化程序不会关心字符串的放置位置，因此如果您想格式化字符串的某些特定部分，则只需提供该部分。

实现此类格式化程序的代码可能如下所示:

public static String format(String text){

    StringBuilder sb = new StringBuilder();
    boolean insideQuote = false;
    char previous = '\0';//to track `\r\n`

    for (char ch : text.toCharArray()) {

        if (insideQuote && 
                 (ch == '\r' || 
                  ch == '\n' && previous != '\r') ) {
            sb.append(" ");//replace `\r` or `\n` with space
        }else {
            if (ch == '"') {
                insideQuote = !insideQuote;
            }
            sb.append(ch); //write other characters without change
        }
        previous = ch;
    }

    return sb.toString();

}

辅助实用方法

public static String format(File file, String encoding) throws IOException {
    String text = new String(Files.readAllBytes(file.toPath()), encoding);
    return format(text);
}

用法:

String formatted = format(new File("input.txt"), "utf-8");
System.out.println(formatted);