Java使用正则表达式分割字符串

Question

我有一个字符串，其内容为ParseGeoPoint[30.132531,31.312511]。如何获取保存在 double 变量中的坐标。即我想要双 lat = 30.132531; 和 double lang = 31.312511;

这是我尝试过的:

String myText = "ParseGeoPoint[30.132531,31.312511]";
String [] latlong= myText.split("["); //it needs an escape character
String [] latlong2= latlong[1].split(",");
Double lat = Double.parseDouble(latlong2[0]);
String[] latlong3= latlong2[1].split("]");//also an escape character is needed here
Double lang = Double.parseDouble(latlong3[0]);

有两件事: 鉴于需要转义字符，如何在方括号上进行拆分？ 第二，我觉得这样做太过分了。一定有更简单的方法。它是什么？

Answer 1

How to split on the square bracket given that it needs an escape character?

我猜你的意思是这不能编译:

String [] latlong= myText.split("[");

要使其编译，请转义 [:

String [] latlong= myText.split("\\[");

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这是使用正则表达式从字符串中提取 double 的另一种方法:

Pattern pattern = Pattern.compile("ParseGeoPoint\\[([\\d.-]+),([\\d.-]+)]");
Matcher matcher = pattern.matcher(myText);
if (matcher.matches()) {
    lat = Double.parseDouble(matcher.group(1));
    lang = Double.parseDouble(matcher.group(2));
}

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另一种方法是使用子字符串:

int bracketStartIndex = myText.indexOf('[');
int commaIndex = myText.indexOf(',');
int bracketEndIndex = myText.indexOf(']');
lat = Double.parseDouble(myText.substring(bracketStartIndex + 1, commaIndex));
lang = Double.parseDouble(myText.substring(commaIndex + 1, bracketEndIndex));