我正在编写一个 GUI,它能够执行一些 JUnit 测试,并且为了处理这个问题,我使用了 SwingWorker。
当我启动程序时,GUI 出现,我单击一些选择,SwingWorker 启动并完成它的一部分,最后输出控制台输出或文件输出。然后我会再次单击 GUI 并开始另一个测试。此时,当程序完成时,它将生成两次最终输出,例如控制台输出后面将直接跟随相同的控制台输出。
我假设这是由于 SwingWorker 没有终止并“死亡”。
此外,当我单击 GUI 中的“开始”按钮时,我正在创建 SwingWorker。这是一个坏主意吗?正确的方法是什么?
编辑添加了代码示例
public class TestMainFrame {
private static JFrame frame;
private static JTextArea textArea;
public TestMainFrame(){
createAndShowGUI();
}
private void createAndShowGUI() {
frame = new JFrame("Test");
frame.setLayout(new BorderLayout());
JButton btn = new JButton("Test Me");
btn.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
if(btn.getText().equals("Test Me")){
testMe();
}
}
});
textArea = new JTextArea("This is a test pane! \n");
textArea.setEditable(false);
JScrollPane scroller = new JScrollPane(textArea);
frame.add(scroller, BorderLayout.CENTER);
frame.add(btn, BorderLayout.PAGE_END);
frame.setSize(new Dimension(300, 400));
frame.setVisible(true);
frame.setLocationRelativeTo(null);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
private static void testMe(){
writeToTextArea("Button Pressed");
writeToTextArea("Starting tests");
SwingWorker<Result, Void> worker = new SwingWorker<Result, Void>() {
@Override
public Result doInBackground() {
writeToTextArea("Inside the doInBackground method of SwingWorker");
return null;
}
@Override
public void done() {
writeToTextArea("The SwingWorker has finished");
}
};
worker.execute();
}
private static void writeToTextArea(String text){
textArea.append(text + "\n");
}
最佳答案
(不是答案)
这就是我运行你的代码的方式:
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class TestMainFrame {
private static JFrame frame;
private static JTextArea textArea;
public TestMainFrame() {
createAndShowGUI();
}
private void createAndShowGUI() {
frame = new JFrame("Test");
frame.setLayout(new BorderLayout());
final JButton btn = new JButton("Test Me");
btn.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
if (btn.getText().equals("Test Me")) {
testMe();
}
}
});
textArea = new JTextArea("This is a test pane! \n");
textArea.setEditable(false);
JScrollPane scroller = new JScrollPane(textArea);
frame.add(scroller, BorderLayout.CENTER);
frame.add(btn, BorderLayout.PAGE_END);
frame.setSize(new Dimension(300, 400));
frame.setVisible(true);
frame.setLocationRelativeTo(null);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
private static void testMe() {
writeToTextArea("Button Pressed");
writeToTextArea("Starting tests");
SwingWorker<Void, Void> worker = new SwingWorker<Void, Void>() {
@Override
public Void doInBackground() {
writeToTextArea("Inside the doInBackground method of SwingWorker");
return null;
}
@Override
public void done() {
writeToTextArea("The SwingWorker has finished");
}
};
worker.execute();
}
// *** note change ***
private static void writeToTextArea(final String text) {
if (SwingUtilities.isEventDispatchThread()) {
textArea.append(text + "\n");
} else {
SwingUtilities.invokeLater(new Runnable() {
public void run() {
textArea.append(text + "\n");
}
});
}
}
public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() {
public void run() {
TestMainFrame testMainFrame = new TestMainFrame();
testMainFrame.createAndShowGUI();
}
});
}
}
关于java - 使用 Swing Worker 在 Swing GUI 中运行 JUnit 测试,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33169510/