递归中的 Java decToHex - 错误的输出顺序

Question

我尝试检查与此问题接近的其他问题，但无法找到适合我的答案，这就是为什么将其作为新帖子发送的原因。希望这不会造成任何问题。

我正在尝试编写一个简单的JAVA代码来进行数字转换——从十进制到八进制或十六进制。对于八进制，一切都很好，但是对于十六进制，输出的顺序错误。就像如果答案是 613 - 程序给出 316。

这是我的完整代码:

import java.util.Scanner;

public class Cem {
    public static void octalconverter(int a) {
        if (a == 0) { //our base
            System.out.println(); //I first put here return a, but then it was adding zeros to the end
        } else {
            System.out.print(a % 8);// first remainder = last digit, and so on
            octalconverter(a / 8); //recursively going till it is base
        }
    }

    public static void hexconverter(int a) {

        if (a == 0) {
            System.out.println();
        } else {

            System.out.print(hexchart(a % 16));
            hexconverter(a / 16);
        }
    }

    public static String hexchart(int a) {
        String result = "";
        if (a <= 9) {
            result = a + result;
        } else {
            if (a == 10)
                result = result + "A";
            // System.out.print("A");
            if (a == 11)
                result = result + "B";
            // System.out.print("B");
            if (a == 12)
                result = result + "C";
            // System.out.print("C");
            if (a == 13)
                result = result + "D";
            //System.out.print("D");
            if (a == 14)
                result = result + "E";
            //System.out.print("E");
            if (a == 15)
                result = result + "F";
            // System.out.print("F");
        }
        return result;
    }

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        Scanner oScan = new Scanner(System.in);
        System.out.println("Please enter your decimal number : "); //getting input
        int num = oScan.nextInt(); //assigning
        System.out.println("Enter 1 for Octal Base Conversion   ####  Enter 2 for Hex Conversion");
        int num2 = oScan.nextInt();

        if (num2 == 1) {
            System.out.print(num + " in Octal(base8) system is : ");
            octalconverter(num); //conversion
        } else if (num2 == 2) {
            System.out.print(num + " in Hexadecimal(base16) system is : ");
            hexconverter(num);
        } else {
            System.out.println("You entered a wrong choice for conversion type, please restart the program");
        }
    }
}

你能告诉我我哪里搞砸了吗？我还必须说我正在寻找我在这里犯的错误，而不是另一种编写此代码的方法。感谢那些愿意分享另一种方式的人，但我再次需要在这里学习我的错误。 谢谢您的帮助

Answer 1

改变

public static void hexconverter(int a) {
    if (a == 0) {
        System.out.println();
    } else {
        System.out.print(hexchart(a % 16));
        hexconverter(a / 16);
    }
}

至

public static void hexconverter(int a) {
    if (a == 0) {
        System.out.println();
    } else {
        hexconverter(a / 16);
        System.out.print(hexchart(a % 16));
    }
}

您的八进制转换也无法正常工作。它以相反的顺序打印。所以也只是交换了这些指令。