java - 如何使用jaxb解析xml

Question

我是 JAXB 新手，我想将 XML 文件读取为 Java 对象，其格式如下:

<payTypeList> 
    <payType>G</payType> 
    <payType>H</payType> 
    <payType>Y</payType> 
 </payTypeList>

请帮助我如何读取这种类型的 XML。

Answer 1

这是您的场景

import java.util.List;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name="payTypeList")
@XmlAccessorType(XmlAccessType.FIELD)
public class PayTypeList {

    @XmlElement
    private List<String> payType;

    public List<String> getPayType() {
        return payType;
    }

    public void setPayType(List<String> payType) {
        this.payType = payType;
    }
}

使用方法

       public static void main(String[] args) throws JAXBException {
            final JAXBContext context = JAXBContext.newInstance(PayTypeList.class);
            final Marshaller m = context.createMarshaller();
            m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

            final PayTypeList paymentType = new PayTypeList();

            List<String> paymentTypes = new ArrayList<String>();
            paymentTypes.add("one");
            paymentTypes.add("two");
            paymentTypes.add("three");
            paymentType.setPayType(paymentTypes);

            m.marshal(paymentType, System.out);
        }

输出.xml

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<payTypeList>
    <payType>one</payType>
    <payType>two</payType>
    <payType>three</payType>
</payTypeList>