java - 查找字符串中所有用点分隔的子字符串？

Question

我有一个很大的字符串，我需要在其中找到所有的存在 模式中的子字符串:

[Word][Dot][Word][Dot]...[Word]

我遇到了一些麻烦，尤其是重复的 [Word][Dot][Word] 模式

这是字符串:

"a.a b..b c.c.c d. .e ff g...g hh.h i.i..i"

这是我当前的模式:

\S+[.{1}]\S+

Matcher.find() 返回这些子字符串:

[0,3] a.a  
[4,8] b..b - shouldn't match  
[9,14] c.c.c  
[24,29] g...g  - shouldn't match  
[30,34] hh.h  
[35,41] i.i..i  - shouldn't match  

我无法让它忽略 b、g、i 子字符串

如有任何帮助，我们将不胜感激。 谢谢!

Answer 1

更明确:

[^\s.]+(?:\.[^\s.]+)+(?!\S)

说明:

[^\s.]+   # Match one or more characters exceopt dot or whitespace
(?:       # Start a non-capturing group
 \.       # Match a dot
 [^\s.]+  # Match one or more characters exceopt dot or whitespace
)+        # Repeat as often as necessary
(?!\S)    # Make sure we don't stop before a non-whitespace character

测试一下 live on regex101.com .

subject = "a.a b..b c.c.c d. .e ff g...g hh.h i.i..i";
result = subject.match(/[^\s.]+(?:\.[^\s.]+)+(?!\S)/g);
document.write(result)