我自己正在学习算法,我尝试从头开始在 Java
中使用泛型类型实现 LinkedList
。我有一个带有 Object
的版本,运行良好,但是当我使用泛型类型更新它时,它会发出警告。谁能帮忙看看“未经检查或不安全的操作”从何而来?
class LinkedListGeneric <T> {
private Node<T> head;
private int size;
public LinkedListGeneric() {
head = null;
size = 0;
}
public int size() {
return size;
}
public void add (T data) {
if (head == null) {
head = new Node<T> (data);
size = 1;
}
else {
Node<T> temp = new Node<T> (data);
search(size).setNext(temp);
size++;
}
}
public void add (T data, int position) {
if (position > size + 1 || position <= 0) {
System.out.println ("error.");
return;
}
Node<T> temp = new Node<T> (data);
if (position == 1) {
temp.setNext(head);
head = temp;
return;
}
Node<T> prev = search(position - 1);
temp.setNext(prev.getNext());
prev.setNext(temp);
}
public void delete (int position) {
if (position > size || position <= 0) {
System.out.println ("error.");
return;
}
if (position == 1) {
size--;
head = head.getNext();
return;
}
Node<T> prev = search(position - 1);
prev.setNext(prev.getNext().getNext());
size--;
}
public T getValue (int position) {
if (position > size || position <= 0) {
System.out.println ("error.");
return null;
}
Node<T> temp = search(position);
return temp.getData();
//return search(position).getData();
}
public int searchData(T data) {
Node<T> temp = head;
int position = 1;
boolean flag = false;
while (temp != null) {
if (temp.getData() == data) {
flag = true;
break;
}
else {
temp = temp.getNext();
position++;
}
}
if (flag) return position;
else return -1;
}
public void print() {
Node<T> temp = head;
int position = 1;
while (temp != null) {
System.out.println("Node " + position + ": " + temp.getData());
temp = temp.getNext();
position++;
}
}
private Node<T> search (int position) {
Node temp = head;
while (position > 0) {
temp = temp.getNext();
}
return temp;
}
private class Node<T> {
private T data;
private Node<T> next;
public Node() {
this.data = null;
next = null;
}
public Node(T data) {
this.data = data;
next = null;
}
public T getData() {
return data;
}
public Node getNext() {
return next;
}
public void setNext(Node next) {
this.next = next;
}
}
}
最佳答案
我看到的问题是你的Node.getNext
调用返回 Node
而不是Node<T>
。这相当于方法返回 Node<Object>
而不是泛型类型。
所以,你应该改变:
public Node getNext() {
return next;
}
至
public Node<T> getNext() {
return next;
}
关于java - 需要有关未经检查的操作java的帮助,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28228530/