我在 Netbeans 8.0.2 中有标准的 Spring 4.x 文件。我在 controllers
包中添加了一个 Controller RegisterController.java
。我还添加了一个模型,一个 User
,其中包含有关用户的一些基本信息。接下来我制作了 2 个 .jsp
文件,Registration.jsp
和 RegistrationSuccess.jsp
。
这是我的 RegisterController:
@Controller
@RequestMapping(value="/register")
public class RegisterController {
@RequestMapping(method=RequestMethod.GET)
public String viewRegistration(Model model){
User user = new User();
model.addAttribute("userForm", user);
List<String> professionList = new ArrayList<>();
professionList.add("Developer");
professionList.add("Designer");
professionList.add("IT Manager");
model.addAttribute("professionList", professionList);
return "Registration";
}
@RequestMapping(method=RequestMethod.POST)
public String processRegistration(@ModelAttribute("userForm") User user, Map<String, Object> Model){
System.out.println("username: " + user.getUsername());
System.out.println("password: " + user.getPassword());
System.out.println("email: " + user.getEmail());
System.out.println("birth date: " + user.getBirthDate());
System.out.println("profession: " + user.getProfession());
return "RegistrationSuccess";
}
}
现在,转到 myProject/register
会导致 404。不过,我对 Spring 如何管理路由感到困惑。有一个 web.xml 看起来像这样:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>redirect.jsp</welcome-file>
</welcome-file-list>
</web-app>
我认为这意味着每个带有 *.htm
的 url 都会转到 dispatcher-servlet:
<?xml version='1.0' encoding='UTF-8' ?>
<!-- was: <?xml version="1.0" encoding="UTF-8"?> -->
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-4.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd">
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>
<!--
Most controllers will use the ControllerClassNameHandlerMapping above, but
for the index controller we are using ParameterizableViewController, so we must
define an explicit mapping for it.
-->
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="index.htm">indexController</prop>
</props>
</property>
</bean>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/"
p:suffix=".jsp" />
<!--
The index controller.
-->
<bean name="indexController"
class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="index" />
</beans>
但是我需要在哪里插入一些条目才能让我的 RegisterController 工作?
最佳答案
由于您在 url 模式中提供了 *.htm,dispatcher-servlet 将只识别 *.htm 请求。 改变你的 web.xml
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
在您的 Controller 之上,无需提供 RequestMapping
。您的方法将为您完成工作
@Controller
public class RegisterController {
在你的方法之上,你应该给值,这样你的方法才能找到它
@RequestMapping(value="/register.htm" method=RequestMethod.GET)
public String viewRegistration(Model model)
关于java - Spring 映射 Url 到 Controller 和 View ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30604072/