java - 给定 7 张牌，获得所有可能的 5 张牌扑克牌

Question

我正在尝试找到在 5 张牌和 2 张底牌的情况下可以形成的 21 手 5 张牌扑克牌。这是我到目前为止所拥有的:

public String[] joinArrays(String[] first, String[] second) {
        String[] result = new String[first.length + second.length];
        for (int i = 0; i < first.length; i++) {
            result[i] = first[i];
        }
        for (int i = 0; i < second.length; i++) {   
            result[i + first.length] = second[i]; 
        }
        return result;
    }

    public String[][] getAllPossibleHands(String[] board, String[] hand){
        String[] allCards = joinArrays(board, hand);
        String[][] allHands = new String[21][5];
        ...
    }

有什么关于从这里去哪里的提示吗？我有一个包含 7 个元素的数组，想要根据这些元素创建可形成的 7C5 (21) 5 元素数组。

谢谢!

Answer 1

对于每手牌，从 7 张牌中选择两张不使用。添加所有其他内容

int cardsSelected = 0;
int hand = 0;
// select first card not to be in the hand
for(int firstCard = 0; firstCard < 7; firstCard++){
    // select first card not to be in the hand
    for(int secondCard = firstCard + 1; secondCard < 7; secondCard++){
        // every card that is not the first or second will added to the hand
        for(int i = 0; i < 7; i++){
            if(i != firstCard && i != secondCard){
                allHands[hand][cardsSelected++] = allCards[i];
            }
        }
        // next hand
        cardsSelected = 0;
        hand++;
    }
}