如何解析“21Jul12”等日期字符串。我尝试过以下方法:
import org.apache.commons.lang.time._
DateUtils.parseDate("21Jul12", Array("ddMMMyy"));
但由于错误而无法工作:
java.text.ParseException: Unable to parse the date: 21Jul21
at org.apache.commons.lang.time.DateUtils.parseDateWithLeniency(DateUtils.java:359)
at org.apache.commons.lang.time.DateUtils.parseDate(DateUtils.java:285)
at .<init>(<console>:20)
at .<clinit>(<console>)
at .<init>(<console>:11)
at .<clinit>(<console>)
at $print(<console>)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at scala.tools.nsc.interpreter.IMain$ReadEvalPrint.call(IMain.scala:704)
at scala.tools.nsc.interpreter.IMain$Request$$anonfun$14.apply(IMain.scala:920)
at scala.tools.nsc.interpreter.Line$$anonfun$1.apply$mcV$sp(Line.scala:43)
at scala.tools.nsc.io.package$$anon$2.run(package.scala:25)
at java.lang.Thread.run(Thread.java:662)
即使我使用java.text.SimpleDateFormat
,我也遇到了类似的异常:
java.text.ParseException: Unparseable date: "21Jul12"
at java.text.DateFormat.parse(DateFormat.java:337)
at .<init>(<console>:13)
at .<clinit>(<console>)
at .<init>(<console>:11)
at .<clinit>(<console>)
at $print(<console>)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at scala.tools.nsc.interpreter.IMain$ReadEvalPrint.call(IMain.scala:704)
at scala.tools.nsc.interpreter.IMain$Request$$anonfun$14.apply(IMain.scala:920)
at scala.tools.nsc.interpreter.Line$$anonfun$1.apply$mcV$sp(Line.scala:43)
at scala.tools.nsc.io.package$$anon$2.run(package.scala:25)
at java.lang.Thread.run(Thread.java:662)
最佳答案
这是要解析上述日期的代码
System.out.println("ddMMMyy >>>" + DateUtils.parseDate("21Jul12", new String[] { "ddMMMyy" }));
System.out.println("yyyy-MM-dd >>>" + DateUtils.parseDate("2012-07-21", new String[] { "yyyy-MM-dd" }));
System.out.println("yyyy MMM dd >>>" + DateUtils.parseDate("2012 Jul 21", new String[] { "yyyy MMM dd" }));
以及控制台上的结果
ddMMMyy >>>Sat Jul 21 00:00:00 CEST 2012
yyyy-MM-dd >>>Sat Jul 21 00:00:00 CEST 2012
yyyy MMM dd >>>Sat Jul 21 00:00:00 CEST 2012
也许您尝试用“ddMMMyy”解析“2012 Jul 21”
System.out.println("ddMMMyy >>>" + DateUtils.parseDate("2012 Jul 21", new String[] { "ddMMMyy" }));
给出你的堆栈
java.text.ParseException: Unable to parse the date: 2012 Jul 21
at org.apache.commons.lang.time.DateUtils.parseDateWithLeniency(DateUtils.java:359)
at org.apache.commons.lang.time.DateUtils.parseDate(DateUtils.java:285)
at com.collibra.dgc.core.model.activity.impl.TestTree.testname(TestTree.java:88)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
关于java - 如何解析 '21Jul12'这样的日期字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12419759/