java - 接受一系列数字？ for循环

Question

我是编程新手，所以我不知道如何编写一个接受一系列数字的程序，并且仅当用户输入 0 时才会退出，然后显示在用户输入 0 之前输入了多少个数字.

我的代码:

import java.util.Scanner;
class Sample {
    public static void main(String[]args) {
        Scanner x = new Scanner(System.in);
        int y;
        int count = 0;

        System.out.print("Enter any number to continue. Enter 0 to stop.");
        num = x.nextInt();
        for(int n = 0; n<=num; n++) { //is this for loop right?
            y = x.nextInt();
            count += y;
        }
        if(num == 0){
            System.out.printf("You entered %d numbers,count");
        }
    }
} // i know my code is missing alot. 

输出应该是这样的。

Enter any number to continue. Enter 0 to stop 
12
11
5
6
1
0
You entered 6 numbers.
2 even
3 odd // i know my code is far from what i want my output to be.
EDIT :
if the user enters 2 then 0 the output should be
You Entered an even number // same with odd. how?

Answer 1

一些线索:

你的线路

num = x.nextInt();

可能会导致编译错误，因为您尚未声明变量 num。

此外，您的循环应该while数字大于 0 时继续。为此，请使用 while 循环:

int num = 1; //some non-zero starting number
while (num != 0) {
    num = x.nextInt();
    count++;
}