我有一个应用程序,我需要检查旅行的持续时间是否在 4 小时到 30 小时之间,我将其存储为字符串 "04:00" 和 "30:00 ",然后我尝试使用 LocalTime.parse()
对其进行解析,"04:00" 已成功解析,但 "30:00" 收到无效格式错误,从字符串中解析持续时间的最佳方法是什么?
最佳答案
首先,您以某种方式存储它是错误的。我建议以 Duration.parse
的方式存储它可以处理,标准 ISO 8601格式。
Examples:
"PT20.345S" -- parses as "20.345 seconds"
"PT15M" -- parses as "15 minutes" (where a minute is 60 seconds)
"PT10H" -- parses as "10 hours" (where an hour is 3600 seconds)
"P2D" -- parses as "2 days" (where a day is 24 hours or 86400 seconds)
"P2DT3H4M" -- parses as "2 days, 3 hours and 4 minutes"
"P-6H3M" -- parses as "-6 hours and +3 minutes"
"-P6H3M" -- parses as "-6 hours and -3 minutes"
"-P-6H+3M" -- parses as "+6 hours and -3 minutes"
那么你可以这样做:
Duration dur30H = Duration.parse("PT30H"); // 30h
Duration dur4H = Duration.parse("PT4H"); // 4h
Duration travelTime = Duration.parse("P1D"); // 1D
boolean result = travelTime.compareTo(dur30H) <= 0 && travelTime.compareTo(dur4H) >= 0; // true
关于JAVA 持续时间,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40847045/