java - 可能的方法来缩短非常大的数字？

Question

这是我程序中双“m”的值(计算后的行星质量，这个值是专门针对地球质量的)

• 5.973405437304745E24

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使用 System.out.println(m) 打印时； 输出为

• 5.973405437304745E24(正确输出)

使用 System.out.println(Math.round(m)) 打印时； 输出为

• 9223372036854775807(输出不正确)

我怎样才能缩短 m 的值以使其在 %6s 之内？ 例如像这样

• 5.97E24

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这是我下面的代码。该作业要求我们以格式化图表输出最终值(正如我在下面尝试做的那样)

//Java imports
import java.util.*;
import java.lang.Math;

//Main class
class Main {
  public static void main(String[] args) {
    //Initializing scanner name userInput
    Scanner userInput = new Scanner (System.in);

    //Greeting statement, prompts user to input the circumference in km
    System.out.println("\nWelcome to the Escape Velocity Application. To begin, please enter the following information below. \nEnter the circumference (km):");

    //Stores circumference in double named "circum" and converts the value to its meter equivalent (unit conversion required)
    double circum = userInput.nextDouble() * Math.pow(10, 3); 

    //Prompts user to input the acceleration in m/s^2
    System.out.println("Enter the acceleration due to gravity (m/s^2):");

    //Stored value in double named "f"
    double f = userInput.nextDouble(); 

    //Gravitational Constant
    double G = 6.67408e-11;

    //1 - Radius calculation using the circumference of a circle formula
    double r = circum/(2*Math.PI);

    //2 - Mass calculation using the gravity formula
    double m = f*Math.pow(r, 2)/G;

    //3 - Calculation escape velocity using the escape velocity formula
    double e = (Math.sqrt((2.0*G*(m))/r));

    //Final output statements
    System.out.println("\nThe radius is: " + Math.round(r * Math.pow(10, -3)) + " kilometers.");
    System.out.println("The mass is: " + m + " kg.");
    System.out.println("The escape velocity is: " + Math.round(e) + " m/s.");

    //Formatted output statements
    System.out.format("\n%20s %6s %10s", "Radius:", Math.round(r * Math.pow(10, -3)), "km.");
    System.out.format("\n%20s %6s %10s", "Mass:", Math.round(m), "kg.");
    System.out.format("\n%20s %6s %10s", "Escape Velocity:", Math.round(e), "m/s.");
  }
}

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这就是输出的样子。由于m值太长，第二行的中心发生了偏移。

The radius is: 6378 kilometers.
The mass is: 5.973405437304745E24 kg.
The escape velocity is: 11181 m/s.

         Radius:   6378        km.
           Mass: 9223372036854775807        kg.
Escape Velocity:  11181       m/s.

Answer 1

您可以使用以下代码:

double x = 5.973405437304745e24;
System.out.printf("Mass: %.2e kg.%n", x);

输出质量:5.97e+24 kg。。

%.2e 格式化数字，%n 仅添加换行符。 .2 指定点后需要两位小数。 e 向格式化程序请求科学计数法。

Math.round() 的问题是，结果存储在无法表示如此大数字的 long 中。