ios - 打开网址 : deprecated in iOS 10

Question

iOS 10 的 Apple 已弃用 openURL: for openURL:option:completionHandler 如果我有:

 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://www.google.com"]];

会变成怎样？ options:<#(nonnull NSDictionary<NSString *,id> *)#>详细

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://www.google.com"] options:<#(nonnull NSDictionary<NSString *,id> *)#> completionHandler:nil];

谢谢

更新 options:@{}对于没有键和值的空字典 http://useyourloaf.com/blog/querying-url-schemes-with-canopenurl/

Answer 1

这样写。

处理完成处理程序

UIApplication *application = [UIApplication sharedApplication];
NSURL *URL = [NSURL URLWithString:@"http://www.google.com"];
[application openURL:URL options:@{} completionHandler:^(BOOL success) {
    if (success) {
         NSLog(@"Opened url");
    }
}];

不处理completionHandler

[application openURL:URL options:@{} completionHandler:nil];

Swift 等价物:- open(_:options:completionHandler:)

UIApplication.shared.open(url)