我是java新手,我试图要求用户输入,但我不希望用户能够输入相同的数字两次。这是我正在尝试的
g1 = iBox.getInteger("Enter your 1st number");
g2 = iBox.getInteger("Enter your 2nd number");
if(g1 == g2){
g2 =iBox.getInteger("Number used, please re-enter");
}
g3 = iBox.getInteger("Enter your 3rd number");
if(g3 == g1){
g3 =iBox.getInteger("Number used, please re-enter");
}
else if(g3 == g2){
g3 =iBox.getInteger("Number used, please re-enter");
}
g4 = iBox.getInteger("Enter your 4th number");
if(g4 == g1){
g4 =iBox.getInteger("Number used, please re-enter");
}
else if(g4 == g2){
g4 =iBox.getInteger("Number used, please re-enter");
}
else if(g4 == g3){
g4 =iBox.getInteger("Number used, please re-enter");
}
oBox.print(" " + g1 + " " + g2 + " " + g3 + " " + g4 + " ");
最佳答案
您应该使用循环和集合。 伪代码:
let S be the set of used numbers(or array, if order is important)
clear contents of S
for I = 1 to N, where N is the number of numbers you want to get
int g = iBox.getInteger("Enter Ith number");
while(S.contains(g))
g = iBox.getInteger("Number used, please re-enter");
Add g into S.
关于java - 用户输入,不允许相同的输入两次,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8477975/