我想建立双向的学生-学科关系。在我注册用户接受纪律之前,一切正常。现在我得到了无限递归。
类看起来像这样:
//Student.java
@Entity
@Table(name = "students")
public class Student {
@NotNull
@Id
@Column(name = "STUDENT_ID")
private String id;
private String name;
@ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinTable(name = "students_disciplines", joinColumns = @JoinColumn(name = "STUDENT_ID"), inverseJoinColumns = @JoinColumn(name = "DISCIPLINE_ID"))
@JsonSerialize(using = NestedDisciplineSetSerializer.class)
private Set<Discipline> disciplines = new HashSet<>();
//Getters, Setters
}
//NestedDisciplineSetSerializer.java
public class NestedDisciplineSetSerializer extends JsonSerializer<Set<Discipline>> {
@Override
public void serialize(Set<Discipline> value, JsonGenerator jgen, SerializerProvider p) throws IOException, JsonProcessingException {
jgen.writeStartArray();
for (Discipline s : value) {
jgen.writeStartObject();
jgen.writeStringField("name", s.getName());
jgen.writeNumberField("id", s.getId());
jgen.writeBooleanField("recommended", s.isRecommended());
jgen.writeEndObject();
}
jgen.writeEndArray();
}
}
//Discipline.java
@Entity`enter code here`
@Table(name = "disciplines")
public class Discipline {
@GeneratedValue(strategy = GenerationType.AUTO)
@Id
@Column(name = "DISCIPLINE_ID")
private int id;
@NotNull
private String name;
@NotNull
private int credits;
private String annotation;
private boolean recommended;
@ManyToMany(mappedBy = "disciplines", fetch = FetchType.EAGER)
@JsonSerialize(using = NestedStudentSetSerializer.class)
private Set<Student> students = new HashSet<>();
//Getters, Setters
}
//NestedStudentSetSerializer.java
public class NestedStudentSetSerializer extends JsonSerializer<Set<Student>> {
@Override
public void serialize(Set<Student> value, JsonGenerator jgen, SerializerProvider p) throws IOException, JsonProcessingException {
jgen.writeStartArray();
for (Student s : value) {
jgen.writeStartObject();
jgen.writeStringField("name", s.getName());
jgen.writeStringField("id", s.getId());
jgen.writeEndObject();
}
jgen.writeEndArray();
}
}
在 Student s = sDao.findOne(id);
试图在这里搜索,但无法找到正确的解决方案。任何事情都会产生相同的结果。
最佳答案
org.hibernate.collection.internal.PersistentSet.hashCode(PersistentSet.java:430) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final] at truelecter.practproekt.entity.Discipline.hashCode(Discipline.java:31) ~[classes/:na] at java.util.HashMap.hash(HashMap.java:338) ~[na:1.8.0_91] at java.util.HashMap.put(HashMap.java:611) ~[na:1.8.0_91] at java.util.HashSet.add(HashSet.java:219) ~[na:1.8.0_91] at java.util.AbstractCollection.addAll(AbstractCollection.java:344) ~[na:1.8.0_91] at org.hibernate.collection.internal.PersistentSet.endRead(PersistentSet.java:327) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final] at org.hibernate.engine.loading.internal.CollectionLoadContext.endLoadingCollection(CollectionLoadContext.java:234) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final] at ... org.hibernate.collection.internal.PersistentSet.hashCode(PersistentSet.java:430) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final] at truelecter.practproekt.entity.Student.hashCode(Student.java:29) ~[classes/:na] at java.util.HashMap.hash(HashMap.java:338) ~[na:1.8.0_91] at java.util.HashMap.put(HashMap.java:611) ~[na:1.8.0_91] at java.util.HashSet.add(HashSet.java:219) ~[na:1.8.0_91] at java.util.AbstractCollection.addAll(AbstractCollection.java:344) ~
我的印象是 Discipline
和 Student
实体的 hashcode()
方法实现同时使用了这两个实体。
也许我错了,在stacktrace中不是很清楚。
您如何为实体定义 equals()
和 hashcode()
方法?
假设实体A
和实体B
具有双向关系。
如果 equals()/hashcode()
实体 A
的实现
在实体 B
字段上调用 equals()/hashcode()
,该字段本身在实体 上调用
字段,你有一个循环。equals()/hashcode()
一个
而你的错误。
此外,即使您通过确保在 equals()/hashcode()/toString()
中只有一个引用另一个来缩短循环,您也应该调用 equals()/hashcode()/toString
实体关系的方法慎用。
它可能会对性能产生真正的影响。如果打开 Hibernate session ,它可能确实会执行您不希望执行的查询。
关于java - 多对多关系中的Hibernate无限循环递归,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40694099/