c++ - 类静态变量初始化顺序

Question

我有一个 A 类，它有两个静态变量。我想用另一个不相关的静态变量初始化一个，就像这样:

#include <iostream>
class A
{
public:
    static int a;
    static int b;
};

int A::a = 200;
int a = 100;
int A::b = a;
int main(int argc, char* argv[])
{
    std::cout << A::b << std::endl;

    return 0;
}

输出是 200。那么，谁能告诉我为什么？

Answer 1

根据查找规则，这是正确的。 [basic.lookup.unqual]/13说:

A name used in the definition of a static data member of class X (after the qualified-id of the static member) is looked up as if the name was used in a member function of X. [ Note: [class.static.data] further describes the restrictions on the use of names in the definition of a static data member.  — end note ]

由于查找不合格的a好像你在一个成员函数中，它必须首先找到成员A::a . A::a 和 A::b 的初始化顺序不会影响查找，但会影响结果的定义程度。