我遇到了 C++ 继承成员函数的问题,请看下面的代码:
binIO_t wtest(path, mode);
const void* Buff = "abcd";
wtest << Buff, 1; //no operator found
wtest.virtIO_t::operator<<(Buff), 1; //works fine
确切的编译器错误是:
Error 1 error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'void *' (or there is no acceptable conversion) ...
我确实遗漏了一些微妙的减速,但我没能找到它。
我的 superclass.h 是:
#pragma once
#include <string>
#include <iostream>
#include <fstream>
#include <stdio.h>
using namespace std;
class virtIO_t{
private:
virtIO_t();
public:
virtIO_t(string filePath, string fileMode);
~virtIO_t();
virtual virtIO_t& operator >> (void* Buf);
virtual virtIO_t& operator << (const void* Buf);
virtual virtIO_t& operator << (const char val) = 0;
virtual virtIO_t& operator >> (char &val) = 0;
};
superclass.cpp 是:
#include "stdafx.h"
#include "virtIO_t.h"
virtIO_t::virtIO_t()
{
}
virtIO_t::~virtIO_t()
{
...
}
virtIO_t::virtIO_t(string filePath, string fileMode){
...
}
virtIO_t& virtIO_t::operator << (const void* Buff){
...
}
virtIO_t& virtIO_t::operator >> (void* Buff){
...
}
sub.h 是:
#pragma once
#include "virtIO_t.h"
class binIO_t : public virtIO_t{
public:
binIO_t(string filePath, string mode);
virtIO_t& operator << (const char val);
virtIO_t& operator >> (char &val);
sub.cpp 是:
#include "stdafx.h"
#include "binIO_t.h"
binIO_t::binIO_t(string filePath, string mode) : virtIO_t(filePath, (string(mode) + "b").c_str()){}
virtIO_t& binIO_t::operator << (const char val){
...
}
virtIO_t& binIO_t::operator >> (char &val){
...
}
最佳答案
binIO_t
声明它自己的 operator<<
隐藏operator<<(void*)
从基类。尝试 using virtIO_t::operator<<
指令或明确定义 operator<<(void*)
在 biunIO_t
.
还有:, 1
什么都不做。
关于C++ 成员函数多态性问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30193123/