我必须使用 CImg 构建图像并使用中点算法绘制三角形,然后使用线性插值法为边缘着色。我很难理解 CImg 库的语法。
我现在只有黑色空白图像。
#include <iostream>
#include "CImg/CImg.h"
using namespace cimg_library;
using namespace std;
int main() {
//Create an empty image
CImg<unsigned char> triangle(255, 255, 1, 3, 0);
//Display and save filtered image
CImgDisplay disp(triangle);
while (!disp.is_closed())
disp.wait();
triangle.save("triangleInterpolation.bmp");
}
最佳答案
这样的东西应该不错...
#include <iostream>
#include <cstdlib>
#define cimg_display 0
#include "CImg.h"
using namespace cimg_library;
using namespace std;
int main() {
// Create 256x256 with radial gradient
CImg<unsigned char> image(256,256,1,3,0);
cimg_forXYC(image,x,y,c) {image(x,y,0,c) = 255-(unsigned char)hypot((float)(128-x),(float)(128-y)); }
// Now overlay a partially opaque 2D interpolated filled triangle for fun
unsigned char cyan[] = { 0, 255, 255 };
unsigned char magenta[] = { 255, 0, 255 };
unsigned char yellow[] = { 255, 255, 0 };
const float opacity=0.6;
image.draw_triangle(
10,10, // 1st vertex x,y
245,10, // 2nd vertex x,y
245,245, // 3rd vertex x,y
cyan, // 1st vertex colour
magenta, // 2nd vertex colour
yellow, // 3rd vertex colour
opacity);
// Save result image as NetPBM PNM - no libraries required
image.save_pnm("result.pnm");
}
关于c++ - 使用CImg绘制三角形并使用插值填充颜色,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48610464/