我正在尝试使用元编程来防止父子结构中的重复代码。我让它工作到一定程度。
底部编译器中显示的代码正确运行,但一些关系(/*Tree_tag,*/
和 /*Parasite_tag*/
)被注释掉了。如果未注释,MSVS2017 显示
error C2664: 'void Obj<std::tuple<Human_tag>,std::tuple<>>::removeParent(const Obj<std::tuple<>,std::tuple<Tree_tag,Dog_tag>> *const )': cannot convert argument 1 from 'Obj<std::tuple<>,std::tuple<Dog_tag>> *' to 'const Obj<std::tuple<>,std::tuple<Tree_tag,Dog_tag>> *const '
note: Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
和 G++ 显示
In instantiation of ‘void Obj<std::tuple<>, std::tuple<_El0, _El ...> ::removeAllChildren() [with TChildTag = Dog_tag; TChildTags = {}]’:
Main.cpp:126:1: required from here
Main.cpp:73:43: error: invalid conversion from ‘Obj<std::tuple<>, std::tuple<Dog_tag> >*’ to ‘const TParent* {aka const Obj<std::tuple<>, std::tuple<Tree_tag, Dog_tag> >*}’ [-fpermissive]
for (auto&& child : childrenPtrs) child->removeParent(this);
问题出在 this
类型限定符。因为我用例如迭代地剥离模板参数
class Obj<std::tuple<>, std::tuple<TChildTag, TChildTags...>>
: public Obj<std::tuple<>, std::tuple<TChildTags...>>
结果this
基类型与原始类型不匹配。如报错所示:Human
的原始类型= Obj<std::tuple<>,std::tuple<Tree_tag,Dog_tag>>
.但是,由于迭代剥离,this
的类型在基地是Obj<std::tuple<>,std::tuple<Dog_tag>>
.
我尝试使用 reinterpret_cast
按照建议:
template<typename T>
void addParent(T* const parentPtr) {
parentsPtrs.push_back(reinterpret_cast<TParent* const>(parentPtr));
}
template<typename T>
void removeParent(T const* const parentPtr) {
auto it = std::find(std::cbegin(parentsPtrs), std::cend(parentsPtrs),
reinterpret_cast<TParent const* const>(parentPtr));
if (it != std::cend(parentsPtrs)) parentsPtrs.erase(it);
}
但问题是所有内容 都被强制转换为允许的参数。 IE。此代码有效:
int main() {
Human h1;
Parasite p1;
addRelation(&h1, &p1);
}
...这应该是不可能的,因为Human
和 Parasite
没有直接关系。
那么我怎样才能正确地保留 this
顶级(最派生)类的类型限定符,符合 Human
, Dog
等类型?
工作代码(带注释):
#include <tuple>
#include <vector>
template<class T>
using prtVector = std::vector<T*>;
class BaseObject {
public:
virtual prtVector<BaseObject> getAllParents() const = 0;
virtual prtVector<BaseObject> getAllChildren() const = 0;
virtual void removeAllParents() = 0;
virtual void removeAllChildren() = 0;
};
template<typename TParentTuple, typename TChilderenTuple>
class Obj;
template<typename TParentTag, typename... TParentTags, typename... TChildTags>
class Obj<std::tuple<TParentTag, TParentTags...>, std::tuple<TChildTags...>>
: public Obj<std::tuple<TParentTags...>, std::tuple<TChildTags...>>
{
using TParent = typename TParentTag::obj_type;
prtVector<TParent> parentsPtrs;
public:
void addParent(TParent* const parentPtr) { parentsPtrs.push_back(parentPtr); }
void removeParent(TParent const* const parentPtr) {
auto it = std::find(std::cbegin(parentsPtrs), std::cend(parentsPtrs), parentPtr);
if (it != std::cend(parentsPtrs)) parentsPtrs.erase(it);
}
virtual prtVector<BaseObject> getAllParents() const override {
auto result = Obj<std::tuple<TParentTags...>, std::tuple<TChildTags...>>::getAllParents();
result.insert(std::begin(result), std::cbegin(parentsPtrs), std::cend(parentsPtrs));
return result;
}
virtual prtVector<BaseObject> getAllChildren() const override {
return Obj<std::tuple<TParentTags...>, std::tuple<TChildTags...>>::getAllChildren();
}
virtual void removeAllParents() override {
Obj<std::tuple<TParentTags...>, std::tuple<TChildTags...>>::removeAllParents();
for (auto&& parent : parentsPtrs) parent->removeChild(this);
}
virtual void removeAllChildren() override {
Obj<std::tuple<TParentTags...>, std::tuple<TChildTags...>>::removeAllChildren();
}
};
template<typename TChildTag, typename... TChildTags>
class Obj<std::tuple<>, std::tuple<TChildTag, TChildTags...>>
: public Obj<std::tuple<>, std::tuple<TChildTags...>>
{
using TChild = typename TChildTag::obj_type;
prtVector<TChild> childrenPtrs;
public:
void addChild(TChild* const childPtr) { childrenPtrs.push_back(childPtr); }
void removeChild(TChild const* const childPtr) {
auto it = std::find(std::cbegin(childrenPtrs), std::cend(childrenPtrs), childPtr);
if (it != std::cend(childrenPtrs)) childrenPtrs.erase(it);
}
virtual prtVector<BaseObject> getAllParents() const override {
return Obj<std::tuple<>, std::tuple<TChildTags...>>::getAllChildren();
}
virtual prtVector<BaseObject> getAllChildren() const override {
auto result = Obj<std::tuple<>, std::tuple<TChildTags...>>::getAllChildren();
result.insert(std::begin(result), std::cbegin(childrenPtrs), std::cend(childrenPtrs));
return result;
}
virtual void removeAllParents() override {}
virtual void removeAllChildren() override {
Obj<std::tuple<>, std::tuple<TChildTags...>>::removeAllChildren();
for (auto&& child : childrenPtrs) child->removeParent(this);
}
};
template<>
class Obj<std::tuple<>, std::tuple<>> : public BaseObject {
public:
virtual prtVector<BaseObject> getAllParents() const override {
return prtVector<BaseObject>();
}
virtual prtVector<BaseObject> getAllChildren() const override {
return prtVector<BaseObject>();
}
virtual void removeAllParents() override {}
virtual void removeAllChildren() override {}
};
struct Human_tag;
struct Tree_tag;
struct Dog_tag;
struct Parasite_tag;
using Human = Obj<std::tuple<>, std::tuple</*Tree_tag,*/ Dog_tag>>;
using Tree = Obj<std::tuple<Human_tag>, std::tuple<>>;
using Dog = Obj<std::tuple<Human_tag>, std::tuple</*Parasite_tag*/>>;
using Parasite = Obj<std::tuple<Dog_tag>, std::tuple<>>;
struct Human_tag { using obj_type = Human; };
struct Tree_tag { using obj_type = Tree; };
struct Dog_tag { using obj_type = Dog; };
struct Parasite_tag { using obj_type = Parasite; };
template<class A, class B>
void addRelation(A* a, B* b)
{
a->addChild(b);
b->addParent(a);
}
#include <iostream>
int main() {
Human h1;
Dog d1, d2;
addRelation(&h1, &d1);
addRelation(&h1, &d2);
auto result = h1.getAllChildren();
std::cout << result.size() << "\n"; //print 2
d1.removeAllParents();
result = h1.getAllChildren();
std::cout << result.size() << "\n"; //print 1
std::cin.ignore();
}
最佳答案
使用 C++17,你可以这样做(不强制转换):
template<typename TParentTuple, typename TChilderenTuple>
class Obj;
template<typename... ParentTags,
typename... ChildTags>
class Obj<std::tuple<ParentTags...>, std::tuple<ChildTags...>> : public BaseObject
{
std::tuple<std::vector<typename ParentTags::obj_type*>...> parents;
std::tuple<std::vector<typename ChildTags::obj_type*>...> children;
public:
template <typename T>
void addParent(T* parent) { std::get<std::vector<T*>>(parents).push_back(parent); }
template <typename T>
void removeParent(const T* parent) {
auto& v = std::get<std::vector<T*>>(parents);
auto it = std::find(std::cbegin(v), std::cend(v), parent);
if (it != std::cend(v)) { v.erase(it); }
}
template <typename T>
void addChild(T* child) { std::get<std::vector<T*>>(children).push_back(child); }
template <typename T>
void removeChild(const T* child) {
auto& v = std::get<std::vector<T*>>(children);
auto it = std::find(std::cbegin(v), std::cend(v), child);
if (it != std::cend(v)) { v.erase(it); }
}
std::vector<BaseObject*> getAllParents() const override {
std::vector<BaseObject*> res;
std::apply([&](auto&... v){ (res.insert(res.end(), v.begin(), v.end()), ...); },
parents);
return res;
}
std::vector<BaseObject*> getAllChildren() const override {
std::vector<BaseObject*> res;
std::apply([&](auto&... v){ (res.insert(res.end(), v.begin(), v.end()), ...); },
children);
return res;
}
void removeAllParents() override {
std::apply(
[this](auto&... v)
{
[[maybe_unused]] auto clean = [this](auto& v) {
for (auto* parent : v) {
parent->removeChild(this);
}
v.clear();
};
(clean(v), ...);
},
parents);
}
void removeAllChildren() override {
std::apply(
[this](auto&... v)
{
[[maybe_unused]] auto clean = [this](auto& v) {
for (auto* child : v) {
child->removeParent(this);
}
v.clear();
};
( clean(v), ...);
},
children);
}
};
在 C++14 中,用 std::apply
替换“for_each_tuple”会更冗长和折叠表达式。
在 C++11 中,更多的是 std::get<T>(tuple)
.
关于c++ - 获取此对象的原始类型,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51173345/