我在将字符串 vector 拆分为更小的整数 vector\数组时遇到问题。我的输入 vector 数据如下所示:
std::vector<std::string> v(2);
v[0] = "0 14 150";
v[1] = "1 2 220";
//...
我知道一个解决方案,制作三个数组并使用 sstream 将数据转换为整数。但我想避免制作“意大利面条”代码。
谢谢, 彼得。
最佳答案
前段时间在stackoverflow上发现了一个split函数。不幸的是,我不能再发布链接了。
void split(const std::string & str, std::vector<std::string>& cont, const std::string & delims)
{
std::size_t current, previous = 0;
current = str.find_first_of(delims);
while (current != std::string::npos)
{
cont.push_back(std::move(str.substr(previous, current - previous)));
previous = current + 1;
current = str.find_first_of(delims, previous);
}
cont.push_back(std::move(str.substr(previous, current - previous)));
}
我需要在您的字符串中使用定界符(在您的情况下似乎是退格符)并在字符串 vector 的每个元素上调用该函数:
int main()
{
std::vector<std::string> vec{ "0 14 150","1 2 220" };
std::vector<std::vector<int>> intVec(3,std::vector<int>(vec.size()));
for (int i = 0; i < vec.size(); i++)
{
std::vector<std::string> singleStr;
split(vec[i], singleStr, " ");
for (int j=0; j < singleStr.size();j++)
intVec[j][i] = (std::stoi(singleStr[j]));
}
system("pause");
}
更通用的解决方案可能如下所示。您可以向 BasicVariant
#include <string>
#include <vector>
class BasicVariant
{
private:
std::string str;
public:
BasicVariant(const std::string& _str) :str(_str) {}
BasicVariant(int value) :str(std::to_string(value)) {}
BasicVariant(double value) :str(std::to_string(value)) {}
inline int toInt()const { return *this; }
inline double toDouble()const { return *this; }
inline std::string toString()const { return *this; }
inline bool toBool()const { return toDouble(); }
inline operator int()const { return std::stoi(str); }
inline operator double()const { return std::stof(str); }
inline operator std::string()const { return str; }
inline operator bool()const { return toDouble(); }
};
template<typename T>
void split(const std::string& str, std::vector<T>& sink, const std::string& delims)
{
std::size_t current, previous = 0;
current = str.find_first_of(delims);
while (current != std::string::npos)
{
sink.push_back(std::move(BasicVariant(str.substr(previous, current - previous))));
previous = current + 1;
current = str.find_first_of(delims, previous);
}
sink.push_back(std::move(BasicVariant(str.substr(previous, current - previous))));
}
int main()
{
std::vector<std::string> vec{ "0 14 150","1 2 220" };
std::vector<std::vector<int>> intVec(3, std::vector<int>(vec.size()));
for (int i = 0; i < vec.size(); i++)
{
std::vector<int> row;
split(vec[i], row, " ");
for (int j = 0; j < row.size(); j++)
intVec[j][i] = row[j];
}
system("pause");
}
关于c++ - 将 vector 拆分为多个数组/vector C++,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54424591/